NEETprep Bank NEET Physics Mechanical Properties of Solids Questions Solved

#3 | Strain

#4 | Hooks's Law & Young's Modules

#5 | Bulk Modules & Shear Modules

#6 | Solved Problems: Set 1

#7 | Extension in a Stretched Wire

#8 | Derivation for Energy Stored in a Wire

#12 | Solved Problems: Set 2

#13 | Solved Problems: Set 3

Concept Questions :-

Stress-strain

elem

$(3) D i f f e r e n t i a t e V P^{n} = C w . r . t o V u \sin g m u l t i p l i c a t i o n r u l e : V \frac{d}{d V} (P^{n}) + P^{n} \frac{d}{d V} (V) = 0 V n P^{n - 1} \frac{d P}{d V} + P^{n} . 1 = 0 V n P^{n - 1} d P + P^{n} . d V = 0 n V P^{n - 1} d P = - P^{n} . d V \Rightarrow \frac{d P}{d V} = - \frac{P^{n}}{n V P^{n - 1}} = - \frac{P}{n V} B u l k M o d u l u s = - \frac{d P}{\frac{d V}{V}} = - (- \frac{P}{\frac{n V}{V}}) = \frac{P}{n}$

Difficulty Level:

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28%
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35%
(3)
28%
(4)
11%

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Q2:

Concept Videos :-

Concept Questions :-

Hooke's law

elem

Difficulty Level:

(1)
14%
(2)
38%
(3)
38%
(4)
11%

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Q3:

Concept Videos :-

#10 | Stress, Strain Curve

#11 | Application of Elastic Behaviour of Material

Concept Questions :-

Stress-strain curve

elem

Difficulty Level:

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18%
(2)
20%
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53%
(4)
11%

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Q4:

Concept Videos :-

#1 | Potential Energy & Elastic Behaviour

Concept Questions :-

Elasticity

elem

Difficulty Level:

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70%
(2)
11%
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6%

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Q5:

Concept Videos :-

#2 | Stress

#3 | Strain

#4 | Hooks's Law & Young's Modules

#5 | Bulk Modules & Shear Modules

#6 | Solved Problems: Set 1

#7 | Extension in a Stretched Wire

#8 | Derivation for Energy Stored in a Wire

#12 | Solved Problems: Set 2

#13 | Solved Problems: Set 3

Concept Questions :-

Stress-strain

elem

Difficulty Level:

(1)
10%
(2)
10%
(3)
10%
(4)
72%

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Q6:

Concept Videos :-

#9 | Poisson Ration

Concept Questions :-

Poisson ratio

elem

Difficulty Level:

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46%
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Q7:

Concept Videos :-

Concept Questions :-

Hooke's law

elem

Difficulty Level:

(1)
12%
(2)
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(3)
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The Young's modulus of a wire of length L and radius r is $Y N / m^{2} .$ If the length and radius are reduced to L/2 and r/2, then its Young's modulus will be -

(a) 1:1 (b) 1:4

Q8:

Concept Videos :-

#2 | Stress

#3 | Strain

#4 | Hooks's Law & Young's Modules

#5 | Bulk Modules & Shear Modules

#6 | Solved Problems: Set 1

#7 | Extension in a Stretched Wire

#8 | Derivation for Energy Stored in a Wire

#12 | Solved Problems: Set 2

#13 | Solved Problems: Set 3

Concept Questions :-

Stress-strain

elem

(b) Young's modulus of wire does not varies with dimension of wire. It is the property of given material.

Difficulty Level:

(1)
69%
(2)
18%
(3)
10%
(4)
5%

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When a certain weight is suspended from a long uniform wire, its length increases by one cm. If the same weight is suspended from another wire of the same material and length but having a diameter half of the first one then the increase in length will be -

(a) 0.5 cm (b) 2 cm

Q9:

Concept Videos :-

Concept Questions :-

Hooke's law

elem

(c)

$l = \frac{F L}{A Y} \Rightarrow 1 \propto \frac{1}{r^{2}} (F, L a n d Y a r e c o n s \tan t) \frac{l_{2}}{l_{1}} = {(\frac{r_{1}}{r_{2}})}^{2} = {(2)}^{2} = 4 \Rightarrow l_{2} = 4 l_{1} = 4 c m$

Difficulty Level:

(1)
19%
(2)
15%
(3)
64%
(4)
5%

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The area of cross-section of a wire of length 1.1 metre is 1 $m m^{2} .$ It is loaded with 1 kg. If Young's modulus of copper is $1.1 \times 10^{11} N / m^{2},$ then the increase in length will be (If $g = 10 m / s^{2}$ )

(a) 0.01 mm (b) 0.075 mm

Q10:

Concept Videos :-

Concept Questions :-

Hooke's law