- 1(current)
Q. No.A wire is suspended from the ceiling and stretched under the action of a weight \(F\) suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.
| (a) | Tensile stress at any cross-section \(A\) of the wire is \(F/A.\) |
| (b) | Tensile stress at any cross-section is zero. |
| (c) | Tensile stress at any cross-section \(A\) of the wire is \(2F/A.\) |
| (d) | Tension at any cross-section \(A\) of the wire is \(F.\) |
Choose the correct option from the given ones:
1. (a) and (b) only
2. (a) and (d) only
3. (b) and (c) only
4. (a) and (c) only
Subtopic: Â Stress - Strain |
 80%
From NCERT
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A rod of length \(l\) and negligible mass is suspended at its two ends by two wires of steel (wire \(A\)) and aluminium (wire \(B\)) of equal lengths (figure). The cross-sectional areas of wires \(A\) and \(B\) are \(1.0~\text{mm}^2\) and \(2.0~\text{mm}^2\) respectively.
\((Y_{\text{Al}}=70\times10^9~\text{N/m}^2\) and \(Y_{\text{steel}}=200\times10^9~\text{N/m}^2)\)
The correct statements are:
\((Y_{\text{Al}}=70\times10^9~\text{N/m}^2\) and \(Y_{\text{steel}}=200\times10^9~\text{N/m}^2)\)
| (a) | The mass \(m\) should be suspended close to wire \(A\) to have equal stresses in both wires. |
| (b) | The mass \(m\) should be suspended close to \(B\) to have equal stresses in both wires. |
| (c) | The mass \(m\) should be suspended in the middle of the wires to have equal stresses in both wires. |
| (d) | The mass \(m\) should be suspended close to wire \(A\) to have equal strain in both wires. |
The correct statements are:
| 1. | (b), (c) | 3. | (b), (d) |
| 2. | (a), (d) | 4. | (c), (d) |
Subtopic: Â Elasticity |Â Stress - Strain |
From NCERT
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
- 1(current)
Q. No.
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