A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to ${\mathrm{L}}_{1}$ when mass M is suspended from its free end. The expression for Young's modulus is:

1. $\frac{\mathrm{Mg}\left({\mathrm{L}}_{1}-\mathrm{L}\right)}{\mathrm{AL}}$

2. $\frac{\mathrm{MgL}}{{\mathrm{AL}}_{1}}$

3. $\frac{\mathrm{MgL}}{\mathrm{A}\left({\mathrm{L}}_{1}-\mathrm{L}\right)}$

4. $\frac{{\mathrm{MgL}}_{1}}{\mathrm{AL}}$

Subtopic:  Elasticity |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

When a block of mass M is suspended by a long wire of length L, the length of the wire becomes (L+l). The elastic potential energy stored in the extended wire is:

1. $\frac{1}{2}\mathrm{MgL}$

2. Mgl

3. MgL

4. $\frac{1}{2}\mathrm{Mgl}$

Subtopic:  Elasticity |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh