The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is: 

1. 3v 

2. 4v 

3. v 

4. 2v 

Subtopic:  Escape velocity |
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A particle of mass 'm' is projected with a velocity v=kVe k<1 from the surface of the earth.

Ve=escape velocity

The maximum height above the surface reached by the particle is:

1. R2k1+k

2. Rk21-k2

3. Rk1-k2

4. Rk1+k2

Subtopic:  Escape velocity |
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A body weighs 72 N on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth?

1. 32 N

2. 30 N

3. 24 N

4. 48 N

Subtopic:  Acceleration due to Gravity |
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What is the depth at which the value of acceleration due to gravity becomes 1/n times the value at the surface of the earth? (radius of the earth = R) 

1.  Rn2

2.  R(n-1)n

3. Rn(n-1)

4. R/n 

Subtopic:  Acceleration due to Gravity |
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The work done to raise a mass m from the surface of the earth to a height h, which is equal to the radius of the earth, is:

1. 32mgR

2. mgR

3. 2mgR

4. 12mgR

Subtopic:  Gravitational Potential Energy |
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A body weighs 200 N on the surface of the earth. How much will it weigh halfway down to the centre of the earth?

1. 100 N

2. 150 N

3. 200 N

4. 250 N

Subtopic:  Acceleration due to Gravity |
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A mass falls from a height 'h' and its time of fall 't' is recorded in terms of time period T of a simple pendulum. On the surface of the earth, it is found that t=2T. The entire set up is taken on the surface of another planet whose mass is half of that of the earth and radius is same. The same experiment is repeated and corresponding times noted as t' and T'. Then we can say:

1. t' = 2T

2. t' > 2T'

3. t' < 2T'

4. t' = 2T'

Subtopic:  Acceleration due to Gravity |
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The time period of a geostationary satellite is 24 h at a height 6RE (RE is the radius of the earth) from the surface of the earth. The time period of another satellite whose height is 2.5RE from the surface, will be:

1. 62h

2. 122h

3. 242.5h

4.  122.5h

Subtopic:  Kepler's Laws |
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Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass m when taken to a height h from the surface of the earth (of radius R and mass M), is given by:

1. GMmR+h

2. GMmhR(R+h)

3. mgh

4. GMmR+h

Subtopic:  Gravitational Potential Energy |
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At what temperature will the RMS speed of oxygen molecules become just sufficient for escaping from the earth's atmosphere? 
(Given : Mass of oxygen molecule (m) = 2.76 x 10-26 kg, Boltzmann's constant kB = 1.38 × 10-23 J K-1):

1. 2.508×104 K

2. 8.360×104 K

3. 5.016×104 K

4. 1.254×104 K

Subtopic:  Escape velocity |
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