- 1(current)
Q. No.The instantaneous angular position of a point on a rotating wheel is given by the equation,
\(\theta(t)=2t^{3}-6t^{2}\)
The torque on the wheel becomes zero at:
1. \(t=0.5\) s
2. \(t=0.25\) s
3. \(t=2\) s
4. \(t=1\) s
\(\theta(t)=2t^{3}-6t^{2}\)
The torque on the wheel becomes zero at:
1. \(t=0.5\) s
2. \(t=0.25\) s
3. \(t=2\) s
4. \(t=1\) s
Subtopic: Â Rotational Motion: Kinematics |
 76%
From NCERT
AIPMT - 2011
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A wheel has an angular acceleration of \(3.0\) rad/s2 and an initial angular speed of \(2.0\) rad/s. In a time of \(2\) s, it has rotated through an angle (in radians) of:
| 1. | \(6\) | 2. | \(10\) |
| 3. | \(12\) | 4. | \(4\) |
Subtopic: Â Rotational Motion: Kinematics |
 83%
From NCERT
AIPMT - 2007
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
Hints
Links
To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
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