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Q. No.A bicyclist comes to a skidding stop in \(10~\text m.\) During this process, the force on the bicycle due to the road is \(200~\text N\) is directly opposed to the motion. The work done by the cycle on the road is:
1. \(+2000~\text J\)
2. \(-200~\text J\)
3. zero
4. \(-20000~\text J\)
Subtopic: Â Work done by constant force |
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The work done by gravity on a projectile of mass \(m\) fired with a speed \(u\) at an angle \(\theta\) to the horizontal, until the time of impact is:
| 1. | zero | 2. | \(-\dfrac12mu^2\cos^2\theta\) |
| 3. | \(-\dfrac12mu^2\sin^2\theta\) | 4. | \(-\dfrac12mu^2\) |
Subtopic: Â Work done by constant force |
 60%
From NCERT
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A force of \(100~\text N\) acts on a block, always acting opposite to its velocity. The block moves from \(x=4~\text m\) to \(x=10~\text m\) and then to \(x=6~\text {m.}\) The work done by the force is:
1. \(200~\text J\)
2. \(-200~\text J\)
3. \(1000~\text J\)
4. \(-1000~\text J\)
1. \(200~\text J\)
2. \(-200~\text J\)
3. \(1000~\text J\)
4. \(-1000~\text J\)
Subtopic: Â Work done by constant force |
From NCERT
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
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Q. No.
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