A force of 5 N making an angle $\theta $ with the horizontal acting on an object displaces it by 0.4 m along the horizontal direction. If the object gains kinetic energy of 1 J then the component of the force is:

1. | 1.5 N | 2. | 2.5 N |

3. | 3.5 N | 4. | 4.5 N |

Subtopic: Work Energy Theorem |

87%

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The bob of a simple pendulum having length l, is displaced from the mean position to an angular position θ with respect to vertical. If it is released, then the velocity of the bob at the lowest position will be:

1. $\sqrt{2gl(1-\mathrm{cos}\theta )}$

2. $\sqrt{2gl(1+\mathrm{cos}}$ $\theta )$

3. $\sqrt{2gl}$ $\mathrm{cos}\theta $

4. $\sqrt{2gl}$

Subtopic: Work Energy Theorem |

79%

From NCERT

AIPMT - 2000

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A block is carried slowly up an inclined plane. If ${\mathrm{W}}_{\mathrm{f}}$ is work done by the friction, ${\mathrm{W}}_{\mathrm{N}}$ is work done by the reaction force, ${\mathrm{W}}_{\mathrm{g}}$ is work done by the gravitational force and ${\mathrm{W}}_{\mathrm{ex}}$ is the work done by an external force, then choose the correct relation(s):

1. ${\mathrm{W}}_{\mathrm{N}}$ $+$ ${\mathrm{W}}_{\mathrm{f}}$ $+$ ${\mathrm{W}}_{\mathrm{g}}$ $+$ ${\mathrm{W}}_{\mathrm{ex}}$ $=$ $0$

2. ${\mathrm{W}}_{\mathrm{N}}$ = 0

3. ${\mathrm{W}}_{\mathrm{ex}}$ $+$ $$ ${\mathrm{W}}_{\mathrm{f}}$ $=$ $-{\mathrm{W}}_{\mathrm{g}}$

4. All of these

Subtopic: Work Energy Theorem |

69%

From NCERT

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A body of mass 'm' is released from the top of a fixed rough inclined plane as shown in the figure. If the frictional force has magnitude F, then the body will reach the bottom with a velocity: $(\mathrm{L}=\sqrt{2}\mathrm{h})$

1. | \(\sqrt{2 g h} \) | 2. | \(\sqrt{\frac{2 F h}{m}} \) |

3. | \(\sqrt{2 g h+\frac{2 F h}{m}} \) | 4. | \(\sqrt{2 g h-\frac{2 \sqrt{2} F h}{m}}\) |

Subtopic: Work Energy Theorem |

62%

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A block is released from rest from a height of h = 5 m. After travelling through the smooth curved surface, it moves on the rough horizontal surface through a length l = 8 m and climbs onto the other smooth curved surface at a height h'. If $\mathrm{\mu}$ = 0.5, find h'.

1. | 2 m | 2. | 3 m |

3. | 1 m | 4. | Zero |

Subtopic: Work Energy Theorem |

64%

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A block of mass 'm' is connected to a spring of force constant K. Initially, the block is at rest and the spring is relaxed. A constant force F is applied horizontally towards the right. The maximum speed of the block will be:

1. | $\frac{\mathrm{F}}{\sqrt{2\mathrm{mK}}}$ | 2. | $\frac{\sqrt{2}\mathrm{F}}{\sqrt{\mathrm{mK}}}$ |

3. | $\frac{\mathrm{F}}{\sqrt{\mathrm{mK}}}$ | 4. | $\frac{2\mathrm{F}}{\sqrt{2\mathrm{mK}}}$ |

Subtopic: Work Energy Theorem |

57%

From NCERT

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