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Q. No.The potential energy function for a particle executing linear simple harmonic motion is given by \(V(x)=\frac{kx^2}{2}\), where \(k\) is the force constant of the oscillator. For \(k=0.5~\text{N/m},\) the graph of \(V(x)\) versus \(x\) is shown in the figure. A particle of total energy \(1~\text J\) moving under this potential must turn back when it reaches:
2. \({x}=\pm 2~\text m\)
3. \({x}=\pm 3~\text m\)
4. \({x}=\pm 4~\text m\)
2. \({x}=\pm 2~\text m\)
3. \({x}=\pm 3~\text m\)
4. \({x}=\pm 4~\text m\)
Subtopic: Â Elastic Potential Energy |
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The figure shows the variation of the kinetic energy of a block of mass m connected to a spring. Kinetic energy at the extreme position for this block of mass m will be:
1.
2.
3.
4. Zero
Subtopic: Â Elastic Potential Energy |
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