The potential energy function for a particle executing linear simple harmonic motion is given by $$V(x)=\frac{kx^2}{2}$$, where $$k$$ is the force constant of the oscillator. For $$k=0.5$$ N/m, the graph of $$V(x)$$ versus $$x$$ is shown in the figure. A particle of total energy $$1$$ J moving under this potential must turn back when it reaches:

1. $$\mathrm{x}=\pm 1$$ m
2. $$\mathrm{x}=\pm 2$$ m
3. $$\mathrm{x}=\pm 3$$ m
4. $$\mathrm{x}=\pm 4$$ m

Subtopic: Â Elastic Potential Energy |
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The figure shows the variation of the kinetic energy of a block of mass m connected to a spring. Kinetic energy at the extreme position for this block of mass m will be:

1. $k{x}_{m}^{2}$

2. $\frac{k{x}_{m}^{2}}{2}$

3. $\frac{k{x}_{m}^{2}}{4}$

4. Zero

Subtopic: Â Elastic Potential Energy |
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