A mass of \(0.5\) kg moving with a speed of \(1.5\) m/s on a horizontal smooth surface, collides with a nearly weightless spring with force constant \(k=50\) N/m. The maximum compression of the spring would be:

1. \(0.12\) m

2. \(1.5\) m

3. \(0.5\) m

4. \(0.15\) m

Subtopic: Elastic Potential Energy |

80%

From NCERT

AIPMT - 2004

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A block of mass *m* initially at rest, is dropped from a height *h* onto a spring of force constant *k*. If the maximum compression in the spring is *x,* then:** **

** **

1. $mgh=\frac{1}{2}k{x}^{2}$

2. $mg(h+x)=\frac{1}{2}k{x}^{2}$

3. $mgh=\frac{1}{2}k{(x+h)}^{2}$

4. $mg(h+x)=\frac{1}{2}k{(x+h)}^{2}$

Subtopic: Elastic Potential Energy |

79%

From NCERT

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A block of mass 2 kg moving with a velocity of 10 m/s on a smooth surface hits a spring of force constant $80\times {10}^{3}$ N/m as shown. The maximum compression in the spring will be:

1. | 5 cm | 2. | 10 cm |

3. | 15 cm | 4. | 20 cm |

Subtopic: Elastic Potential Energy |

80%

From NCERT

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A spring 40 mm long is stretched by the application of force. If 10 N force is required to stretch the spring through 1 mm, then work done to stretch the spring 40 mm is equal to:

1. | 84 J | 2. | 68 J |

3. | 23 J | 4. | 8 J |

Subtopic: Elastic Potential Energy |

70%

From NCERT

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When a spring is subjected to 4 N force, its length is a metre and if 5 N is applied, its length is b metre. If 9 N is applied, its length will be:

1. 4b – 3a

2. 5b – a

3. 5b – 4a

4. 5b – 2a

Subtopic: Elastic Potential Energy |

69%

From NCERT

AIPMT - 1999

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A block of mass *\(\text M\)* moving on the frictionless horizontal surface collides with the spring of spring constant \(\text K\)and compresses it by length *\(\text L\)*. The maximum momentum of the block after the collision will be:

** **

1. | Zero | 2. | \(ML^2 \over K\) |

3. | \(\sqrt{MK}~L\) | 4. | \(KL^2 \over 2M\) |

Subtopic: Elastic Potential Energy |

68%

From NCERT

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If two springs, A and B $({K}_{A}$ $=$ $2$ ${K}_{B}),$ are stretched by the same suspended weights, then the ratio of work done in stretching is equal to:

1. 1 : 2

2. 2 : 1

3. 1 : 1

4. 1 : 4

Subtopic: Elastic Potential Energy |

63%

From NCERT

AIPMT - 1999

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A weight 'mg' is suspended from a spring. The energy stored in the spring is U. The elongation in the spring is:

1. $\frac{2\mathrm{U}}{\mathrm{mg}}$

2. $\frac{\mathrm{U}}{\mathrm{mg}}$

3. $\frac{\sqrt{2}\mathrm{U}}{\mathrm{mg}}$

4. $\frac{\mathrm{U}}{\sqrt{2}\mathrm{mg}}$

Subtopic: Elastic Potential Energy |

62%

From NCERT

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Two springs of spring constants k and 3k are stretched separately by the same force. The ratio of potential energy stored in them respectively, will be:

1. | 3: 1 | 2. | 9: 1 |

3. | 1: 3 | 4. | 1: 9 |

Subtopic: Elastic Potential Energy |

69%

From NCERT

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A vertical spring with a force constant *\(k\)* is fixed on a table. A ball of mass *\(m\)* at a height *\(h\)* above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance *\(d\)*. The net work done in the process is:

1. \(mg(h+d)+\frac{1}{2}kd^2\)

2. \(mg(h+d)-\frac{1}{2}kd^2\)

3. \(mg(h-d)-\frac{1}{2}kd^2\)

4. \(mg(h-d)+\frac{1}{2}kd^2\)

Subtopic: Elastic Potential Energy |

64%

From NCERT

AIPMT - 2007

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