The potential energy \(\mathrm{U}\) of a system is given by (where \(\mathrm{x}\) is the position of its particle and \(\mathrm{A},\) \(\mathrm{B}\) are constants). The magnitude of the force acting on the particle is:
1. constant
2. proportional to \(\mathrm{x}\)
3. proportional to
4. proportional to
The potential energy of a particle varies with distance \(r\) as shown in the graph. The force acting on the particle is equal to zero at:
1. \(P\)
2. \(S\)
3. both \(Q\) and \(R\)
4. both \(P\) and \(S\)
A particle is moving such that the potential energy U varies with position in metre as U (x) = ( - 2x + 50) J. The particle will be in equilibrium at:
1. x = 25 cm
2. x = 2.5 cm
3. x = 25 m
4. x = 2.5 m
1. | \(\dfrac{B}{A}\) | 2. | \(\dfrac{B}{2A}\) |
3. | \(\dfrac{2A}{B}\) | 4. | \(\dfrac{A}{B}\) |
Potential energy \((U)\) related to coordinates is given by; \(U=3(x+y).\) Work done by the conservative force when the particle is going from \((0,0), (2,3)\) is:
1. \(15\) J
2. \(-15\) J
3. \(12\) J
4. \(10\) J
The potential energy of a particle of mass m varies as the magnitude of the The magnitude of the acceleration of the particle at (0, 3) is: (symbols have their usual meaning)
1.
2.
3.
4. Zero
The figure shows the potential energy function U(x) for a system in which a particle is in a one-dimensional motion. What is the direction of the force when the particle is in region AB? (symbols have their usual meanings)
1. The positive direction of x
2. The negative direction of X
3. Force is zero, so direction not defined
4. The negative direction of y
A particle of mass 'm' is moving in a horizontal circle of radius 'r' under a centripetal force equal to –K/r2, where K is a constant. The total energy of the particle will be:
1.
2.
3.
4.
The diagram represents a particle's potential energy curve in a field. The particle will be in equilibrium at which position(s):
1. \(B\) and \(D\)
2. \(A\) and \(C\)
3. \(A,B\) and \(C\)
4. \(A,B,C\) and \(D\)