The relationship between force and position is shown in the given figure (in a one-dimensional case). The work done by the force in displacing a body from $$x = 1$$ cm to $$x = 5$$ cm is:

1. $$20$$ ergs
2. $$60$$ ergs
3. $$70$$ ergs
4. $$700$$ ergs

Subtopic:  Work Done by Variable Force |
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A position dependent force $$F=7-2x+3x^2$$ N acts on a small body of mass $$2$$ kg and displaces it from $$x = 0$$ to $$x = 5$$ m. The work done in joule is:

 1 $$70$$ 2 $$270$$ 3 $$35$$ 4 $$135$$
Subtopic:  Work Done by Variable Force |
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A position-dependent force $\mathrm{F}$ $=$ $6$ $+$ $8\mathrm{x}$ $-$ $3{\mathrm{x}}^{2}$ $\mathrm{N}$ acts on a small body of mass 3 kg, displacing it from x = 0 to x = 2 m. The work done in joule is:

1. 20 J

2.  40 J

3. 10 J

4.  12 J

Subtopic:  Work Done by Variable Force |
82%
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A body is displaced from (0, 0) to (1m, 1m) along the path x=y by a force $F=\left({x}^{2}\stackrel{^}{j}+y\stackrel{^}{i}\right)N$. The work done by this force will be :

1. $\frac{4}{3}J$

2. $\frac{5}{6}J$

3. $\frac{3}{2}J$

4. $\frac{7}{5}J$

Subtopic:  Work Done by Variable Force |
77%
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A block of mass $$10$$ kg, moving in the $$x\text-$$direction with a constant speed of $$10$$ ms-1, is subjected to a retarding force $$F=0.1x$$ J/m during its travel from $$x =20$$ m to $$30$$ m. Its final kinetic energy will be:

 1 $$475$$ J 2 $$450$$ J 3 $$275$$ J 4 $$250$$ J
Subtopic:  Work Done by Variable Force |
72%
From NCERT
NEET - 2015
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A force $$F = (20 + 10 y)$$ acts on a particle in the $$y$$-direction where $$F$$ is in Newton and $$y$$ is in meter. Work done by this force to move the particle from $$y =0$$ to $$y =1$$ m is:
1. $$20~\text{J}$$
2. $$30~\text{J}$$
3. $$5~\text{J}$$
4. $$25~\text{J}$$
Subtopic:  Work Done by Variable Force |
74%
From NCERT
NEET - 2019
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When a body moves non-uniformly on a circular path:
 1 no work is done by the tangential force. 2 no work is done by the centripetal force. 3 work done by the tangential force is always positive. 4 work done by the centripetal force is negative.
Subtopic:  Work Done by Variable Force |
69%
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A force $\mathbit{F}=-k\left(y\mathbit{i}+x\mathbit{j}\right)$ (where k is a positive constant) acts on a particle moving in the xy-plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force on the particle is:

1. $-2k{a}^{2}$

2. $2k{a}^{2}$

3. $-k{a}^{2}$

4. $$ka^2$$

Subtopic:  Work Done by Variable Force |
56%
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The relationship between the force F and the position x of a body is as shown in the figure. The work done in displacing the body from x = 1 m to x = 5 m will be:

 1 30 J 2 15 J 3 25 J 4 20 J
Subtopic:  Work Done by Variable Force |
52%
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The graph between the resistive force $$F$$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $$25$$ kg and the initial velocity is $$2$$ m/s. When the distance covered by the body is $$4$$ m, its kinetic energy would be:

1. $$50$$ J
2. $$40$$ J
3. $$20$$ J
4. $$10$$ J

Subtopic:  Work Done by Variable Force |
53%
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