A force \(F = (20 + 10 y)\) acts on a particle in the \(y\)-direction where \(F\) is in Newton and \(y\) is in metre. The work done by this force to move the particle from \(y =0\) to \(y =1~\text m\) is:
1. \(20~\text{J}\)
2. \(30~\text{J}\)
3. \(5~\text{J}\)
4. \(25~\text{J}\)
Subtopic:  Work Done by Variable Force |
 76%
From NCERT
NEET - 2019
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An object of mass \(500~\text g\) initially at rest is acted upon by a variable force whose \(x\)-component varies with \(x\) in the manner shown. The velocities of the object at the points \(x=8~\text m\) and \(x=12~\text m\) would have the respective values of nearly:

           

1. \(18~\text {m/s}\)  and \(22.4~\text {m/s}\)  2. \(23~\text {m/s}\)  and \(22.4~\text {m/s}\) 
3. \(23~\text {m/s}\)  and \(20.6~\text {m/s}\)  4. \(18~\text {m/s}\)  and \(20.6~\text {m/s}\) 
Subtopic:  Work Done by Variable Force |
 60%
From NCERT
NEET - 2019
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