A force $$F = (20 + 10 y)$$ acts on a particle in the $$y$$-direction where $$F$$ is in Newton and $$y$$ is in meter. Work done by this force to move the particle from $$y =0$$ to $$y =1$$ m is:
1. $$20~\text{J}$$
2. $$30~\text{J}$$
3. $$5~\text{J}$$
4. $$25~\text{J}$$
Subtopic: Â Work Done by Variable Force |
Â 74%
From NCERT
NEET - 2019
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An object of mass $$500$$ g initially at rest is acted upon by a variable force whose x-component varies with $$x$$ in the manner shown. The velocities of the object at the points $$x=8$$ m and $$x=12$$ m would have the respective values of nearly:

 1 $$18$$ m/s and $$22.4$$ m/s 2 $$23$$ m/s and $$22.4$$ m/s 3 $$23$$ m/s and $$20.6$$ m/s 4 $$18$$ m/s and $$20.6$$ m/s
Subtopic: Â Work Done by Variable Force |
Â 59%
From NCERT
NEET - 2019
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
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