The values of energy required to break one bond in DNA \((10^{-20}~\mathrm{J})\) and the kinetic energy of an air molecule \((10^{-21}~\mathrm{J})\) in eV respectively are:

1.	\(0.6\) eV and \(0.06\) eV
2.	\(0.006\) eV and \(0.06\) eV
3.	\(0.06\) eV and \(0.06\) eV
4.	\(0.06\) eV and \(0.006\) eV

An elevator can carry a maximum load of \(1800~\text{kg}\) (elevator + passengers), moving up with a constant speed of \(2~\text{m/s}.\) The frictional force opposing the motion is \(4000~\text{N}.\) The minimum power delivered by the motor to the elevator is:
1. \(59000~\text{W}\) 
2. \(44000~\text{W}\) 
3. \(11000~\text{W}\) 
4. \(22000~\text{W}\) 

In a nuclear reactor, a neutron of high speed (typically \(\left(10\right)^{7}\) m/s) must be slowed to \(\left(10\right)^{3}\) m/s so that it can have a high probability of interacting with isotope \(^{235}_{92}U\) and causing it to fission. The material making up the light nuclei, usually heavy water \(\left(D_{2} O\right)\) or graphite, is called a moderator. Find the fraction of the kinetic energy of the neutron lost by it in an elastic collision with light nuclei like deuterium.

1.  \(\dfrac{1}{9}\)

2.  \(\dfrac{8}{9}\)

3.  \(\dfrac{9}{8}\)

4.  \(\dfrac{1}{8}\)

Consider the collision depicted in the figure below to be between two billiard balls with equal masses \(m_{1}   =   m_{2}\). The first ball is called the cue while the second ball is called the target. The billiard player wants to ‘sink’ the target ball in a corner pocket, which is at an angle \(\left(\theta\right)_{2}=37^\circ\). Assume that the collision is elastic and that friction and rotational motion are not important. \(\left(\theta\right)_{1}\) is:

1. \(53^{o}\)

2. \(0^{o}\)

3. \(37^{o}\)

4. \(30^{o}\)

The value of the daily intake of a human adult $\left({10}^7<mspace\; width="1em"></mspace>\mathrm{J}\right)$ in kilocalories is:

1.   24 k cal

2.   2.4 kcal

3.   2400 kcal

4.   240 kcal

To simulate car accidents, auto manufacturers study the collisions of moving cars with mounted springs of different spring constants. Consider a typical simulation with a car of mass \(1000~\text{kg}\) moving with a speed of \(18~\text{km/h}\) on a rough road and colliding with a horizontally mounted spring of spring constant \(2.5\times 10^3~\text{N/m}\)$\mathrm{}$. If the coefficient of friction between road and tyre of the car, \(\mu\), to be \(0.375\). Maximum compression of the spring is:
1. \(3.5~\text{m}\)
2. \(2.0~\text{m}\)
3. \(1.5~\text{m}\)
4. \(2.5~\text{m}\)

A bob of mass m is suspended by a light string of length \(L.\) It is imparted a horizontal velocity \(v_0\) at the lowest point \(A\) such that it completes a semi-circular trajectory in the vertical plane with the string becoming slack only on reaching the topmost point, the ratio of the kinetic energies \(\dfrac{K_B}{K_C}\) ${\mathrm{}}_{}$at points \({B}\) and \({C}\) is: