NEET and AIPMT NEET Physics Laws of Motion MCQ Questions Solved


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If acceleration of wedge is 'a'From wedge frame:

                           

Block is in equilibrium   ma cos θ=mg sin θ        a=g tan θ        a=g34           tan 37°=34   For whole system,          Mg=M+4+1a     asys=Net driving forceMass of system          Mg=M+53g4              4M=3M+15               M=15 kg

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At the point, where the block leaves the circle T=0

Using conservation of energy from A to B-

Ui+Ki = Uf+KfO+12mu2 = mgl+l sinθ+12mv2   v2=u2-2gl+lsinθ                ............iAt point B-   T=0 mg sinθ = mv2l      v2=gl sinθput it in i   lg sinθ = xgl-2gl-2gl sinθ   3l sinθ=x-2l       sinθ=x-2/3h=l+lsinθ=l+lx-23h=lx+13

v=xglh=x+13lwhere h is height where body leave the circle.h=72+13l=3l2

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Tmax=mv12R+mg = mv12+mgRRTmin=mv22R-mg = mv22-mgRRAs,    TmaxTmin = 4=v12+gRv22-gR             4v22-gR = v12+gR                     v12 = 4v22-5gR                ............iConserving enerfy from L to H -          12mv12 = 12mv22 + 2mgR               v12 = v22 + 4gR                        ...........iiOn comparing both equations-            4v22-5gR = v22 + 4gR            3v22 = 9gR               v22 = 3×10×103            v2=10 m/s

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length of the element = R×2θmass of full length = mmass of unit length = m2πRmass of the element = m2πR×R×2θ                              dm =m2π×θ

2TSinθ=dmv2R= mπ×Q×v2RAs, θ is very small, Sinθθ 2=mπ×Q×v2R       T=mv22πR

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