A ball is traveling with uniform translatory motion. This means that:

1. it is at rest.

2. the path can be a straight line or circular and the ball travels with uniform speed.

3. all parts of the ball have the same velocity (magnitude and direction) and the velocity is constant.

4. the center of the ball moves with constant velocity and the ball spins about its center uniformly.

Subtopic:  Newton's Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

A meter scale is moving with uniform velocity. This implies:

1. the force acting on the scale is zero, but a torque about the centre of mass can act on the scale.

2. the force acting on the scale is zero and the torque acting about the centre of mass of the scale is also zero.

3. the total force acting on it need not zero but the torque on it is zero.

4. neither the force nor the torque needs to be zero.

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

A cricket ball of mass 150 g has an initial velocity $\mathrm{u}=\left(3\stackrel{^}{\mathrm{i}}+4\stackrel{^}{\mathrm{j}}\right){\mathrm{ms}}^{-1}$ and a  final velocity$\mathrm{v}=-\left(3\stackrel{^}{\mathrm{i}}+4\stackrel{^}{\mathrm{j}}\right){\mathrm{ms}}^{-1}$, after being hit. The change in momentum (final momentum-initial momentum) is (in kgm/s)

$$1.~zero$$
$$2.~-\left ( 0.45\hat{i}+0.6\hat{j} \right )$$
$$3.~-\left ( 0.9\hat{i}+1.2\hat{j} \right )$$
$$4.~-5\left ( \hat{i} +\hat{j}\right )$$

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

In the previous problem (3), the magnitude of the momentum transferred during the hit is:

1. zero
2. 0.75 kg-ms-1
3. 1.5 kg-ms-1
4. 14 kg-ms-1

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

Conservation of momentum in a collision between particles can be understood from

1. Conservation of energy
2. Newton's first law only
3. Newton's second law only
4. Both Newton's second and third law

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

A hockey player is moving northward and suddenly turns westward at the same speed to avoid an opponent. The force that acts on the player is

1. frictional force along westward
2. muscle force along southward
3. frictional force along south-West
4. muscle force a south-West

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

A body of mass 2kg travels according to the law $\mathrm{x}\left(\mathrm{t}\right)=\mathrm{pt}+{\mathrm{qt}}^{2}+{\mathrm{rt}}^{3}$ where, . The force acting on the body at t=2s is

1. 136 N
2. 134 N
3. 158 N
4. 68 N

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

A body with a mass of 5 kg is acted upon by a force $\mathrm{F}=\left(-3\stackrel{^}{\mathrm{i}}+4\stackrel{^}{\mathrm{j}}\right)\mathrm{N}$. If its initial velocity at t = 0 is $v=\left(6\stackrel{^}{i}-12\stackrel{^}{j}\right)m{s}^{-1}$, the time at which it will just have a velocity along the Y-axis is

1.  never
2.  10 s
3. 2 s
4. 15 s

Subtopic:  Types of Forces | Newton's Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

A car of mass m starts from rest and acquires a velocity along the east, $\mathrm{v}=\mathrm{v}\stackrel{^}{\mathrm{i}}\left(\mathrm{v}>0\right)$ in two seconds. Assuming the car moves with uniform acceleration, the force exerted on the car is

1. mv/2 eastward and is exerted by the car engine

2. mv/2 eastward and is due to the friction on the tires exerted by the road

3. more than mv/2 eastward exerted due to the engine and overcomes the friction of the road

4. mv/2 exerted by the engine

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The motion of a particle of mass m is given by x = 0 for t < 0s, x(t) = A sin 4$\mathrm{\pi }$t for 0 < t < (1/ 4)s (A > 0), and x = 0 for t > (1/4) s. Then:

(a) The force at t = (1/8)s on the particle is $-16{\pi }^{2}Am$
(b) The particle is acted upon by an impulse of magnitude 4${\mathrm{\pi }}^{}$Am at t =0 s and t =(1/4) s
(c) The particle is not acted upon by any force
(d) The particle is not acted upon by a constant force
(e) There is no impulse acting on the particle

Which of the following statement/s is/are true?

1. (a, c, d, e)

2. (a, c)

3. (b, c, d)

4. (a, b, d)

Subtopic:  Newton's Laws | Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh