A block of mass \(m\) is placed on a smooth inclined wedge \(ABC\) of inclination \(\theta\) as shown in the figure. The wedge is given an acceleration '\(a\)' towards the right. The relation between \(a\) and \(\theta\) for the block to remain stationary on the wedge is:
          
1. \(a = \dfrac{g}{\mathrm{cosec }~ \theta}\)
2. \(a = \dfrac{g}{\sin\theta}\)
3. \(a = g\cos\theta\)
4. \(a = g\tan\theta\)

Subtopic:  Application of Laws |
 79%
From NCERT
NEET - 2018
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
Links
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital