A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and $\mathrm{\theta }$ for the block to remain stationary on the wedge is:

1. $a=\frac{g}{\mathrm{cos}ec\theta }$

2. $a=\frac{g}{\mathrm{sin}\theta }$

3.

4.

Subtopic:  Application of Laws |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh