# Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is 0.05. (  mass of the string is negligible and no other friction exists ). 1. 1.25  2. 1.50   3. 1.66  4. 1.00

Subtopic:  Friction |
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A point mass 'm' is moved in a vertical circle of radius 'r' with the help of a string. The velocity of the mass is $\sqrt{7\mathrm{gr}}$ at the lowest point. The tension in the string at the lowest point is:

1. 6mg

2. 7mg

3. 8mg

4. 1mg

Subtopic:  Non Uniform Vertical Circular Motion |
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A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is  nearly:

1. 2.1 kg m/s

2. 1.4 kg m/s

3. 0 kg m/s

4. 4.2 kg m/s

Subtopic:  Application of Laws |
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Two bodies of mass, 4 kg and 6 kg, are tied to the ends of a massless string. The string passes over a pulley, which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity (g) is: 1.  g/2

2.  g/5

3.  g/10

4.  g

Subtopic:  Application of Laws |
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A shell of mass m is at rest initially. It explodes into three fragments having masses in the ratio 2:2:1. If the fragments having equal masses fly off along mutually perpendicular directions with speed v, the speed of the third (lighter) fragment is:
1.$$3 \sqrt{2} v$$
2. $$v$$
3. $$\sqrt{2} v$$
4. $$2 \sqrt{2} v$$
Subtopic:  Newton's Laws |
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Assertion (A): A standing bus suddenly accelerates. If there was no friction between the feet of a passenger and the floor of the bus, the passenger would move back.
Reason (R): In the absence of friction, the floor of the bus would slip forward under the feet of the passenger.

1. (A) is true but (R) is false.
2. (A) is false but (R) is true.
3. Both (A) and (R) are true and (R) is the correct explanation of (A).
4. Both (A) and (R) are true but (R) is not the correct explanation of (A).

Subtopic:  Newton's Laws |
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When a body of mass 'm' just begins to slide as shown, match list-I with list-II:

 List-I List-II (a) Normal reaction (i) P (b) Frictional force (fs) (ii) Q (c) Weight (mg) (iii) R (d) mgsin$$\theta ~$$ (iv) S Choose the correct answer from the options given below:
 (a) (b) (c) (d) 1. (ii) (i) (iii) (iv) 2. (iv) (ii) (iii) (i) 3. (iv) (iii) (ii) (i) 4. (ii) (iii) (iv) (i)
Subtopic:  Application of Laws |
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In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Consider the surface to be smooth):
Given g = 10 ms-2  1.  25 N
2.  39 N
3.  6 N
4.  10 N
Subtopic:  Tension & Normal Reaction |
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A body of mass m is kept on a rough horizontal surface (coefficient of friction= $\mu$). A horizontal force is applied to the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by $\stackrel{\to }{F}$, where:

1. $|\stackrel{\to }{F}|=mg+\mu mg$

2. $|\stackrel{\to }{F}|=\mu mg$

3. $|\stackrel{\to }{F}|\le mg\sqrt{1+{\mu }^{2}}$

4. $|\stackrel{\to }{F}|=mg$

Subtopic:  Friction |
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A truck is stationary and has a bob suspended by a light string in a frame attached to the truck. The truck suddenly moves to the right with an acceleration of a. In the frame of the truck, the pendulum will tilt:

1. to the left and angle of inclination of the pendulum with the vertical is ${\mathrm{sin}}^{-1}\left(\frac{a}{g}\right)$

2. to the left and angle of inclination of the pendulum with the vertical is ${\mathrm{cos}}^{-1}\left(\frac{a}{g}\right)$

3. to the left and angle of inclination of the pendulum with the vertical is ${\mathrm{tan}}^{-1}\left(\frac{a}{g}\right)$

4. to the left and angle of inclination of the pendulum with the vertical is ${\mathrm{tan}}^{-1}\left(\frac{g}{a}\right)$

Subtopic:  Application of Laws |
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