A particle is projected at an angle with horizontal with an initital speed u. When it makes an angle with horizontal, its speed v is-
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A body is projected with velocity m/s with an angle of projection 60 with horizontal. Calculate velocity on that point where body makes an angle 30 with the horizontal.
1. 20 m/s
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4. 10 m/s
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A particle is moving with veocity ; where k is constant. The general equation for path is:
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4. xy=constant
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A body thrown vertically so as to reach its maximum height in t second. The total time from the time of projection to reach a point at half of its maximum height while returning (in second) is:
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A particle is projected with a velocity u making an angle with the horizontal. At any instant, its velocity v is at right angles to its initial velocity u; then v is:
1. u cos
2. u tan
3. u cot
4. u sec
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A projectile is given an initial velocity of . The cartesian equation of its path is (g = 10 )
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A ship A is moving westwards with a speed of 10 km and a ship B, 100 km south of A is moving northwards with a speed of 10 km . The time after which the distance between them becomes the shortest, is:
1. 5 hr
2. hr
3. hr
4. 0 hr
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Time taken by the projectile to reach from A to B is t. Then the distance AB is equal to :
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4. 2ut
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A particle projected with kinetic energy with an angle of projection . Then the variation of kinetic K with vertical displacement y is
1. linear
2. parabolic
3. hyperbolic
4. periodic
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Three particles moving with constant velocities and V respectively as given in the figure. After some time all three particles are in the same line, then relation among and V is
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