A particle is moving with velocity v=k(yi^+xj^) where k is a constant. The general equation for the path will be:

1. y = x2 + constant 2. y2 = x2 + constant
3. y = x + constant 4. xy=constant

Subtopic:  Speed & Velocity |
 54%
From NCERT
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A body is thrown vertically so as to reach its maximum height in t second. The total time from the time of projection to reach a point at half of its maximum height while returning (in second) is:

1. 2t

2. 1+12t

3. 3t2

4. t2

Subtopic:  Projectile Motion |
 68%
From NCERT
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Three particles are moving with constant velocities v1, v2 and v respectively as given in the figure. After some time, if all the three particles are in the same line, then the relation among v1, v2 and v is:
                                    
1.  v= v1 + v2

2.  v= v1v2

3.  v=v1v2v1+v2

4.  v= 2v1v2v1+v2

Subtopic:  Speed & Velocity |
 53%
From NCERT
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A particle starts from the origin at t=0 and moves in the x-y plane with a constant acceleration 'a' in the y direction. Its equation of motion is y=bx2. The x component of its velocity (at t=0) will be:

1. variable

2. 2ab

3. a2b

4. a2b

Subtopic:  Acceleration |
From NCERT
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A boat moves with a speed of 5 km/h relative to water in a river flowing with a speed of 3 km/h. Width of the river is 1 km. The minimum time taken for a round trip will be

1. 5 min

2. 60 min

3. 20 min

4. 30 min

Subtopic:  Relative Motion |
 55%
From NCERT
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A river is flowing from W to E with a speed of 5 m/min. A man can swim in still water with a velocity of 10 m/min. In which direction should the man swim so as to take the shortest possible path to go to the south. 

1. 30° with downstream

2. 60° with downstream

3. 120° with downstream

4. South

Subtopic:  Relative Motion |
 59%
From NCERT
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Certain neutron stars are believed to be rotating at about 1 rev/s. If such a star has a radius of 20 km, the acceleration of an object on the equator of the star will be:

1. \(20 \times 10^8 \mathrm{~m} / \mathrm{s}^2 \) 2. \(8 \times 10^5 \mathrm{~m} / \mathrm{s}^2 \)
3. \(120 \times 10^5 \mathrm{~m} / \mathrm{s}^2 \) 4. \(4 \times 10^8 \mathrm{~m} / \mathrm{s}^2\)
Subtopic:  Circular Motion |
 69%
From NCERT
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In 1.0 s, a particle goes from point A to point B, moving in a semicircle of radius 1.0 m (see figure). The magnitude of the average velocity is:
                   

1. 3.14 m/s 2. 2.0 m/s
3. 1.0 m/s 4. Zero
Subtopic:  Speed & Velocity |
 76%
From NCERT
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The angle turned by a body undergoing circular motion depends on the time as given by the equation, θ=θ0+θ1t+θ2t2. It can be deduced that the angular acceleration of the body is? 

1. θ1

2. θ2

3. 2θ1

4. 2θ2

Subtopic:  Circular Motion |
 84%
From NCERT
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A particle is moving eastwards with velocity of 5 m/s. In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is?

1. Zero
2.  \(\frac{1}{\sqrt{2}} \mathrm{~m} / \mathrm{s}^2 \) toward north-west
3.  \(\frac{1}{\sqrt{2}} \mathrm{~m} / \mathrm{s}^2 \) toward north-east
4.  \(\frac{1}{2} m / s^2 \)  toward north-west

Subtopic:  Acceleration |
 63%
From NCERT
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