The position of a particle is given by; \(\vec{r}=(3.0t\hat{i}-2.0t^{2}\hat{j}+4.0\hat{k})\) m 
 where \(t\) is in seconds and the coefficients have the proper units for \(r\) to be in meters. The magnitude and direction of \(\vec{v}(t)\) at \(t=1.0\) s are:

1. \(4\) m/s \(53^\circ\) with x-axis
2. \(4\) m/s \(37^\circ\) with x-axis
3. \(5\) m/s \(53^\circ\) with y-axis
4. \(5\) m/s \(53^\circ\) with x-axis
Subtopic:  Speed & Velocity |
 66%
From NCERT
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh