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Q. No.The position of a particle is given by;
\(\vec r(t)=4t\hat i+2t^2\hat j+5\hat k\)
where \(t\) is in seconds and \(r\) in metre. Find the magnitude and direction of velocity \(v(t)\), at \(t=1~\mathrm{s}\), with respect to \(x\)-axis:
\(\vec r(t)=4t\hat i+2t^2\hat j+5\hat k\)
where \(t\) is in seconds and \(r\) in metre. Find the magnitude and direction of velocity \(v(t)\), at \(t=1~\mathrm{s}\), with respect to \(x\)-axis:
| 1. | \(4\sqrt2~\text{ms}^{-1},45^\circ\) | 2. | \(4\sqrt2~\text{ms}^{-1},60^\circ\) |
| 3. | \(3\sqrt2~\text{ms}^{-1},30^\circ\) | 4. | \(3\sqrt2~\text{ms}^{-1},45^\circ\) |
Subtopic: Â Speed & Velocity |
 79%
From NCERT
NEET - 2023
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