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Q. No.A particle of mass 10g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to 8x10-4 J by the end of the second revolution after the beginning of the motion?
1. 0.15 m/s2
2. 0.18 m/s2
3. 0.2 m/s2
4. 0.1 m/s2
Subtopic: Circular Motion |
From NCERT
NEET - 2016
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In the given figure, \(a=15\) m/s2 represents the total acceleration of a particle moving in the clockwise direction in a circle of radius \(R=2.5\) m at a given instant of time. The speed of the particle is:
1. \(4.5\) m/s
2. \(5.0\) m/s
3. \(5.7\) m/s
4. \(6.2\) m/s
Subtopic: Circular Motion |
61%
From NCERT
NEET - 2016
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A particle moves so that its position vector is given by, \(\vec{r}=\cos \omega t ~\hat{x}+ \sin \omega t~ \hat{y },\) where \(\omega\) is a constant. Which of the following is true?
| 1. | The velocity and acceleration both are parallel to \(\vec{r }.\) |
| 2. | The velocity is perpendicular to \(\vec{r }\) and acceleration is directed towards to origin. |
| 3. | The velocity is parallel to \(\vec{r }\) and acceleration is directed away from the origin. |
| 4. | The velocity and acceleration both are perpendicular to \(\vec{r}.\) |
Subtopic: Circular Motion |
78%
From NCERT
NEET - 2016
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A particle of mass \(10\) g moves along a circle of radius \(6.4\) cm with a constant tangential acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to \(8 \times 10^{-4}\) J by the end of the second revolution after the beginning of the motion?
| 1. | \(0.15\) m/s2 | 2. | \(0.18\) m/s2 |
| 3. | \(0.2\) m/s2 | 4. | \(0.1\) m/s2 |
Subtopic: Circular Motion |
52%
From NCERT
NEET - 2016
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
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