A balloon ascends upward with a constant upward velocity \(5\) m/s. At the same time it is being pushed to the right by the wind with a speed that is proportional to its height \((y)\):    \(v_\text{right}=2y\)
where the units are in SI. The acceleration of the balloon is: 
1.  zero
2.  \(10\) m/s2 to right
3.  \(5\) m/s2 to right
4.  \(10\) m/s2 upward




 
Subtopic:  Acceleration |
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.

Mark the correct statements for a particle going on a straight line:

(a) if the velocity and acceleration have opposite sign, the object is slowing down.
(b) if the position and velocity have opposite sign, the particle is moving towards the origin.
(c) if the velocity is zero at an instant, the acceleration should also be zero at that instant.
(d) if the velocity is zero for a time interval, the acceleration is zero at any instant within the time interval.


Choose the correct option:

1. (a), (b) and (c)
2. (a), (b) and (d)
3. (b), (c) and (d)
4. all of these
Subtopic:  Acceleration |
 64%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity \(\mathrm{v_0}\) and the braking capacity, or deceleration, \(-a\) that is caused by the braking. Expression for stopping distance of a vehicle in terms of \(\mathrm{v_0}\) and \(a\) is:

1. \(\frac{\mathrm{v_o}^2}{2a}\) 2. \(\frac{\mathrm{v_o}}{2a}\)
3. \(\frac{\mathrm{v_o}^2}{a}\) 4. \(\frac{2a}{\mathrm{v_o}^2}\)
Subtopic:  Acceleration |
 82%
From NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

advertisementadvertisement

A particle moves a distance \(x\) in time \(t\) according to equation \(x=(t+5)^{-1}.\) The acceleration of the particle is proportional to:
1. (velocity)\(3/2\)
2. (distance)\(2\)
3. (distance)\(-2\)
4. (velocity)\(2/3\)

Subtopic:  Acceleration |
 70%
From NCERT
AIPMT - 2010
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch

A particle moves along a straight line such that its velocity is proportional to the square root of its displacement. Its acceleration is:
 
1. zero
2. constant
3. proportional to time
4. proportional to displacement
Subtopic:  Acceleration |
 67%
From NCERT
Please attempt this question first.
Hints
Please attempt this question first.