A balloon ascends upward with a constant upward velocity $$5$$ m/s. At the same time it is being pushed to the right by the wind with a speed that is proportional to its height $$(y)$$:    $$v_\text{right}=2y$$
where the units are in SI. The acceleration of the balloon is:
1.  zero
2.  $$10$$ m/s2 to right
3.  $$5$$ m/s2 to right
4.  $$10$$ m/s2 upward

Subtopic: Â Acceleration |
From NCERT
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Mark the correct statements for a particle going on a straight line:

 (a) if the velocity and acceleration have opposite sign, the object is slowing down. (b) if the position and velocity have opposite sign, the particle is moving towards the origin. (c) if the velocity is zero at an instant, the acceleration should also be zero at that instant. (d) if the velocity is zero for a time interval, the acceleration is zero at any instant within the time interval.

Choose the correct option:

 1 (a), (b) and (c) 2 (a), (b) and (d) 3 (b), (c) and (d) 4 all of these
Subtopic: Â Acceleration |
Â 64%
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When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity $$\mathrm{v_0}$$ and the braking capacity, or deceleration, $$-a$$ that is caused by the braking. Expression for stopping distance of a vehicle in terms of $$\mathrm{v_0}$$ and $$a$$ is:

 1 $$\frac{\mathrm{v_o}^2}{2a}$$ 2 $$\frac{\mathrm{v_o}}{2a}$$ 3 $$\frac{\mathrm{v_o}^2}{a}$$ 4 $$\frac{2a}{\mathrm{v_o}^2}$$
Subtopic: Â Acceleration |
Â 82%
From NCERT
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A particle moves a distance $$x$$ in time $$t$$ according to equation $$x=(t+5)^{-1}.$$ The acceleration of the particle is proportional to:
1. (velocity)$$3/2$$
2. (distance)$$2$$
3. (distance)$$-2$$
4. (velocity)$$2/3$$

Subtopic: Â Acceleration |
Â 70%
From NCERT
AIPMT - 2010
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