The motion of a particle is given by the equation S=(3t3+7t2+14t+8)m, The value of the acceleration of the particle at t = 1 s is :

1. 10 m/s2 2. 32 m/s2
3. 23 m/s2 4. 16 m/s2
Subtopic:  Acceleration |
 93%
From NCERT
AIPMT - 2000
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The position \(x\) of a particle varies with time \(t\) as \(x=at^2-bt^3\). The acceleration of the particle will be zero at time \(t\) equal to:
1. \(\frac{a}{b}\)
2. \(\frac{2a}{3b}\)
3. \(\frac{a}{3b}\)
4. zero

Subtopic:  Acceleration |
 84%
From NCERT
PMT - 1997
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A body is moving along a straight line according to the equation of motion, x=t2-3t+4, where x is in metre and t is in seconds. What is the acceleration of the body when it comes to rest?

1. Zero

2. 2 m/s2

3. 32 m/s2

4. 1 m/s2

Subtopic:  Acceleration |
 84%
From NCERT
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A particle starting from rest undergoes a rectilinear motion with an acceleration \(a\). The variation of acceleration with time \(t\) is shown in the diagram. The final velocity of the object during its motion is:
                  

1. \(6\) m/s
2. \(16\) m/s
3. \(24\) m/s
4. \(12\) m/s
Subtopic:  Acceleration |
 83%
From NCERT
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A particle moves along a straight line such that its displacement at any time t is given by S=t36t2+3t+4 metres. The velocity when the acceleration is zero is:

1. 4 ms-1 2. −12 ms−1
3. 42 ms−1 4. −9 ms−1
Subtopic:  Acceleration |
 81%
From NCERT
PMT - 1994
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The acceleration ‘a’ in m/s2 of a particle is given by a=3t2+2t+2 where t is the time. If the particle starts out with a velocity, u = 2 m/s at t = 0, then the velocity at the end of 2 seconds will be:

1. 12 m/s

2. 18 m/s

3. 27 m/s

4. 36 m/s

Subtopic:  Acceleration |
 72%
From NCERT
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When the velocity of a body is variable, then:

1. its speed may be constant
2. its acceleration may be constant
3. its average acceleration may be constant
4. all of the above
Subtopic:  Acceleration |
 70%
From NCERT
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If the velocity of a particle is given by v=(18016x)1/2 m/s, then its acceleration will be: 

1. Zero

2. 8 m/s2

3. – 8 m/s2

4. 4 m/s

Subtopic:  Acceleration |
 67%
From NCERT
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A particle moves a distance \(x\) in time \(t\) according to equation \(x = (t+5)^{-1}\). The acceleration of the particle is proportional to: 

1. \((\text{velocity})^{\frac{3}{2}}\) 2. \((\text{distance})^2\)
3. \((\text{distance})^{-2}\) 4. \((\text{velocity})^{\frac{2}{3}}\)
Subtopic:  Acceleration |
 65%
From NCERT
NEET - 2010
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If a particle has negative velocity and negative acceleration, its speed:

1. increases
2. decreases
3. remains the same
4. zero


 

Subtopic:  Acceleration |
 66%
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