- 1(current)
Q. No.The displacement of a particle is given by \(y = a + bt + ct^{2} - dt^{4}\). The initial velocity and acceleration are, respectively:
| 1. | \(b, -4d\) | 2. | \(-b,2c\) |
| 3. | \(b, ~2c\) | 4. | \(2c, -2d\) |
Subtopic: Non Uniform Acceleration |
82%
From NCERT
PMT - 1999
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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to \(v(x)= βx^{- 2 n}\) where \(\beta\) and \(n\) are constants and \(x\) is the position of the particle. The acceleration of the particle as a function of \(x\) is given by:
| 1. | \(- 2 nβ^{2} x^{- 2 n - 1}\) | 2. | \(- 2 nβ^{2} x^{- 4 n - 1}\) |
| 3. | \(- 2 \beta^{2} x^{- 2 n + 1}\) | 4. | \(- 2 nβ^{2} x^{- 4 n + 1}\) |
Subtopic: Non Uniform Acceleration |
69%
From NCERT
NEET - 2015
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NEET 2026 - Target Batch - Vital
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The acceleration of a particle starting from rest varies with time according to the relation \(A= - a\omega^2\sin \omega t\). The displacement of this particle at a time \(t\) will be:
| 1. | \(-\frac{1}{2}\left(a\omega^2\sin\omega t\right)t^2\) | 2. | \(a\omega \sin \omega t\) |
| 3. | \(a\omega \cos \omega t\) | 4. | \(a\sin \omega t\) |
Subtopic: Non Uniform Acceleration |
61%
From NCERT
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A particle is moving along the \(x\)-axis such that its velocity varies with time as per the equation \(v = 20\left(1-\frac{t}{2}\right) \). At \(t=0 \) particle is at the origin. From the following, select the correct position \((x)\) - time \((t)\) plot for the particle:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
Subtopic: Non Uniform Acceleration |
60%
From NCERT
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- 1(current)
Q. No.
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