The position \(x\) of a particle varies with time \(t\) as \(x=at^2-bt^3\). The acceleration of the particle will be zero at time \(t\) equal to:

1. \(\dfrac{a}{b}\) 2. \(\dfrac{2a}{3b}\)
3. \(\dfrac{a}{3b}\) 4. zero
 
Subtopic:  Acceleration |
 85%
From NCERT
PMT - 1997
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When the velocity of a body is variable, then:

1. its speed may be constant
2. its acceleration may be constant
3. its average acceleration may be constant
4. all of the above
Subtopic:  Acceleration |
 71%
From NCERT
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A particle moves a distance \(x\) in time \(t\) according to equation \(x = (t+5)^{-1}\). The acceleration of the particle is proportional to: 

1. \((\text{velocity})^{\frac{3}{2}}\) 2. \((\text{distance})^2\)
3. \((\text{distance})^{-2}\) 4. \((\text{velocity})^{\frac{2}{3}}\)
Subtopic:  Acceleration |
 66%
From NCERT
NEET - 2010
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A body is projected vertically in the upward direction from the surface of the earth. If the upward direction is taken as positive, then the acceleration of the body during its upward and downward journey is:
1. Positive, negative
2. Negative, negative
3. Positive, positive
4. Negative, positive

Subtopic:  Acceleration |
 63%
From NCERT
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The velocity \(v\) of an object varies with its position \(x\) on a straight line as \(v=3\sqrt{x}.\) Its acceleration versus time \((a\text-t)\) graph is best represented by:

1.        2.    
3. 4.   
Subtopic:  Acceleration |
 61%
From NCERT
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