Suppose you are riding a bike with a speed of \(20\) m/s due east relative to a person \(A\) who is walking on the ground towards the east. If your friend \(B\) walking on the ground due west measures your speed as \(30\) m/s due east, find the relative velocity between two reference frames \(A\) and \(B\):

1. The velocity of \(A\) with respect to \(B\) is \(5\) m/s towards the east.
2. The velocity of \(A\) with respect to \(B\) is \(5\) m/s towards the west.
3. The velocity of \(A\) with respect to \(B\) is \(10\) m/s towards the east.
4. The velocity of \(A\) with respect to \(B\) is \(10\) m/s towards the west.

Subtopic:  Relative Motion in One Dimension |
 63%
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A particle is moving along the \(x\)-axis such that its velocity varies with time as per the equation \(v = 20\left(1-\frac{t}{2}\right)\). At \(t=0\) particle is at the origin. From the following, select the correct position \((x)\) - time \((t)\) plot for the particle:

1.    2.
3. 4.

 
Subtopic:  Non Uniform Acceleration |
 58%
From NCERT
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The velocity \(v\) of an object varies with its position \(x\) on a straight line as \(v=3\sqrt{x}.\) Its acceleration versus time \((a\text-t)\) graph is best represented by:

1.        2.    
3. 4.   
Subtopic:  Acceleration |
 61%
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The displacement \((x)\) of a point moving in a straight line is given by; \(x=8t^2-4t.\) Then the velocity of the particle is zero at:

1. \(0.4\) s 2. \(0.25\) s
3. \(0.5\) s 4. \(0.3\) s
Subtopic:  Instantaneous Speed & Instantaneous Velocity |
 87%
From NCERT
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An elevator whose floor to ceiling height is \(12\) meters, moves upward with an acceleration of \(2.2~\text{m/s}^2\). After \(1.5\) seconds since starting, a bolt falls from its ceiling. The time taken by the bolt to reach the floor is:
1. \(1~\text{s}\)
2. \(2~\text{s}\)
3. \(\sqrt{2}~\text{s}\)
4. \(\sqrt{3}~\text{s}\)

Subtopic:  Relative Motion in One Dimension |
 64%
From NCERT
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A ball is thrown vertically downwards with a velocity of \(20\) m/s from the top of a tower. It hits the ground after some time with the velocity of \(80\) m/s . The height of the tower is: (assuming \(g = 10~\text{m/s}^2)\)

1. \(340\) m 2. \(320\) m
3. \(300\) m 4. \(360\) m
Subtopic:  Uniformly Accelerated Motion |
 83%
From NCERT
NEET - 2020
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The position (\(x\)) of a particle in a straight line motion is given by \(x = 2 + 10 t - 5 t^{2}~\text{m}\). Its velocity (\(v\)) is best represented by?

1. 2.
3. 4.
Subtopic:  Graphs |
 76%
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A body starting from rest moves with uniform acceleration on a horizontal surface. The body covers \(3\) consecutive equal distances from the beginning in time \(t_1, t_2,\text{and}~t_3\) seconds. The ratio of \(t_1:t_2:t_3\) is:
1. \(1:2:3\)
2. \(1:\sqrt{2}:\sqrt{3}\)
3. \(1:\left(\sqrt{2}-1\right):\left(\sqrt{3}-\sqrt{2}\right)\)
4. \(\sqrt{3}:\sqrt{2}:1\)

Subtopic:  Uniformly Accelerated Motion |
 79%
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A particle starts from rest (with constant acceleration) and acquires velocity \(20\) m/s in \(5\) s. The distance travelled by the particle in the next \(2\) s will be:

1. \(50\) m 2. \(48\) m
3. \(100\) m 4. \(150\) m
Subtopic:  Uniformly Accelerated Motion |
 73%
From NCERT
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A drunkard walking in a narrow lane takes \(5\) steps forward and \(3\) steps backward, followed again by \(5\) steps forward and \(3\) steps backward, and so on. Each step is \(1\) m long and requires \(1\) s. There is a pit on the road \(13\) m away from the starting point. The drunkard will fall into the pit after:

1. \(37\) s 2. \(31\) s
3. \(29\) s 4. \(33\) s
Subtopic:  Distance & Displacement |
 62%
From NCERT
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