# 1. ${\left({\mathrm{A}}^{2}+{\mathrm{B}}^{2}+\frac{\mathrm{AB}}{\sqrt{3}}\right)}^{1/2}$ 2. A+B 3. ${\left({\mathrm{A}}^{2}+{\mathrm{B}}^{2}+\sqrt{3}\mathrm{AB}\right)}^{1/2}$ 4. ${\left({\mathrm{A}}^{2}+{\mathrm{B}}^{2}+\mathrm{AB}\right)}^{1/2}$

Subtopic:  Scalar Product | Vector Product |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

If   then angle between A and B will be :-

1.  $90°$

2. $120°$

3. $0°$

4. $60°$

Subtopic:  Resultant of Vectors |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The vector sum of two forces is perpendicular to their vector difference. In this case, the two forces:

1. Are equal

2. Have the same magnitude

3. Are not equal in magnitude

4. Cannot be predicted

Subtopic:  Resultant of Vectors |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

If the angle between the vector is θ, the value of the product $\left(\stackrel{\to }{\mathrm{B}}×\stackrel{\to }{\mathrm{A}}\right)\cdot \stackrel{\to }{\mathrm{A}}$ is equal to

1. zero

2. BA2sinθcosθ

3. BA2cosθ

4. BA2sinθ

Subtopic:  Scalar Product | Vector Product |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

If a vector ($2\stackrel{^}{\mathrm{i}}+3\stackrel{^}{j}+8\stackrel{^}{k}$) is perpendicular to the vector ($4\stackrel{^}{\mathrm{i}}-4\stackrel{^}{j}+\mathrm{\alpha }\stackrel{^}{k}$), then the value of $\mathrm{\alpha is}$

1. -1

2. $-\frac{1}{2}$

3. $\frac{1}{2}$

4. 1

Subtopic:  Scalar Product |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

The vectors  are such that: $\left|\stackrel{\to }{\mathrm{A}}+\stackrel{\to }{\mathrm{B}}\right|=\left|\stackrel{\to }{\mathrm{A}}-\stackrel{\to }{\mathrm{B}}\right|$.
The angle between the two vectors is:

1. 90o

2. 60o

3. 75o

4. 45o

Subtopic:  Resultant of Vectors |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

$\stackrel{\to }{\mathrm{A}}$ and $\stackrel{\to }{\mathrm{B}}$ are two vectors and θ is the angle between them. If $\left|\stackrel{\to }{\mathrm{A}}×\stackrel{\to }{\mathrm{B}}\right|=\sqrt{3}\left(\stackrel{\to }{A}.\stackrel{\to }{B}\right)$, then the value of θ will be:

1. 60o

2. 45o

3. 30o

4. 90o

Subtopic:  Scalar Product | Vector Product |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

Three forces acting on a body are shown in the figure. To have the resultant force only along the y-direction, the magnitude of the minimum additional force needed is

1.

2.

3.

4.

Subtopic:  Resultant of Vectors |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

Six vectors $\stackrel{\to }{\mathrm{a}}$ through $\stackrel{\to }{\mathrm{f}}$ have the magnitudes and directions indicated in the figure. Which of the following statements is true?

1. $\stackrel{\to }{\mathrm{b}}+\stackrel{\to }{\mathrm{c}}=\stackrel{\to }{\mathrm{f}}$

2. $\stackrel{\to }{\mathrm{d}}+\stackrel{\to }{\mathrm{c}}=\stackrel{\to }{\mathrm{f}}$

3. $\stackrel{\to }{\mathrm{d}}+\stackrel{\to }{\mathrm{e}}=\stackrel{\to }{\mathrm{f}}$

4. $\stackrel{\to }{\mathrm{b}}+\stackrel{\to }{\mathrm{e}}=\stackrel{\to }{\mathrm{f}}$

Subtopic:  Resultant of Vectors |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
Launched MCQ Practice Books

Prefer Books for Question Practice? Get NEETprep's Unique MCQ Books with Online Audio/Video/Text Solutions via Telegram Bot

If vectors $\stackrel{\to }{\mathrm{A}}=\mathrm{cos\omega t}\stackrel{^}{\mathrm{i}}+\mathrm{sin\omega t}\stackrel{^}{\mathrm{j}}$ and  are functions of time. Then, at what value of t are they orthogonal to one another?

1. $\mathrm{t}=\frac{\mathrm{\pi }}{4\mathrm{\omega }}$

2. $\mathrm{t}=\frac{\mathrm{\pi }}{2\mathrm{\omega }}$

3. $\mathrm{t}=\frac{\mathrm{\pi }}{\mathrm{\omega }}$

4. $\mathrm{t}=0$

Subtopic:  Scalar Product |
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh
To view explanation, please take trial in the course below.
NEET 2023 - Target Batch - Aryan Raj Singh