The dimensional formula of pressure is:
1. \(\left[MLT^{-2}\right]\)
2. \(\left[ML^{-1}T^{2}\right]\)
3. \(\left[ML^{-1}T^{-2}\right]\)
4. \(\left[MLT^{2}\right]\)

The measurements are made as 18.425 cm, 7.21 cm, and 5.0 cm. The addition of these measurements should be written as:

1. 30.635 cm

2. 30.64 cm

3. 30.63 cm

4. 30.6 cm

A physical parameter '\(a\)' can be determined by measuring the parameters \(b\), \(c\), \(d\) and \(e\) using the relation\(,a= \frac{b^{\alpha}c^{\beta}}{d^{\gamma}e^{\delta}}.\) If the maximum errors in the measurement of \(b, ~c, ~d,~\text{and}~e\) are \(b_1\%,~c_1\%,~d_1\%~\text{and}~e_1\%\), then the maximum error in the value of '\(a\)' determined by the experiment is:
1.  \((b_1+c_1+d_1+e_1)\%\)
2.  \((b_1+c_1-d_1-e_1)\%\)
3.  \(\alpha b_1+\beta c_1-\gamma d_1-\delta e_1\%\)
4.  \(\alpha b_1+\beta c_1+\gamma d_1+\delta e_1\%\)

A light-year is a unit of: 
1. Time
2. Mass
3. Distance
4. Energy

In $$\(S= a+bt+ct^2,~S\) is measured in metres and \(t\) in seconds. The unit of \(c\) will be:

Temperature can be expressed as a derived quantity in terms of any of the following:

If \(u_1\) and \(u_2\) are the units selected in two systems of measurement and \(n_1\) and \(n_2\) are their numerical values, then:

Given the equation \(\left(P+\frac{a}{V^2}\right)(V-b)=\text {constant}\). The units of \(a\) will be: (where \(P\) is pressure and \(V\) is volume)
1. \(\text{dyne} \times \text{cm}^5\)
2. \(\text{dyne} \times \text{cm}^4\)
3. \(\text{dyne} / \text{cm}^3\)
4. \(\text{dyne} / \text{cm}^2\)

The dimensions of a couple are:
1. \(\left[ML^2T^{-2}\right]\)
2. \(\left[MLT^{-2}\right]\)
3. \(\left[ML^{-1}T^{-3}\right]\)
4. \(\left[ML^{-2}T^{-2}\right]\)

The dimensional formula for impulse is:
1. \([MLT^{-2}]\)
2.  \([MLT^{-1}]\)
3.  \([ML^2T^{-1}]\)
4. \([M^2LT^{-1}]\)