- 1(current)
Q. No.The nitration of aniline in a strong acidic medium results in the formation of m-nitroaniline because:
1.
In spite of substituents nitro group always goes to only m-position
2.
In electrophilic substitution reactions amino group is meta directive
3.
In absence of substituents nitro group always goes to only m-position
4.
In an acidic (strong) medium aniline is present as anilinium ion
A nitrogen-containing aromatic compound A reacts with Sn/HCl, followed by HNO2 to give an unstable compound B. On treatment with phenol, B forms a beautiful coloured compound C with the molecular formula C12H10N2O. The structure of compound A is:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
The correct statement regarding the basicity of arylamines is:
| 1. | Arylamines are generally more basic than alkylamines because the lone-pair electrons of nitrogen are not delocalized by interaction with the aromatic ring π-electron system. |
| 2. | Arylamines are generally more basic than alkylamines because of the aryl group +I effect. |
| 3. | Arylamines are generally more basic than alkylamines because the nitrogen atom in arylamines is sp-hybridized. |
| 4. | Arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalized by interaction with the aromatic ring π-electron system. |
Mark the correct reaction among the following to convert acetamide to methenamine:
1. Hoffmann bromamide reaction
2. Stephens reaction
3. Gabriels phthalimide synthesis
4. Carbylamine reaction
Mark the correct increasing order of basic strength of given molecules:
 |
 |
 |
| (I) | (II) | (III) |
1. III < I < II
2. III < II < I
3. II < I < III
4. II < III < I
Which of the following reactions is appropriate for converting acetamide to methanamine?
1. Hoffmann hypobromamide reaction
2. Stephens reaction
3. Gabriels phthalimide synthesis
4. Carbylamine reaction
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Q. No.
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