Intermediates formed during the reaction of ${\mathrm{RCNH}}_2$
$$ $$ $$ $\left|\right|$
$$ $$ $$ $\mathrm{O}$ with ${\mathrm{Br}}_2$ and KOH are:

1. RNHCOBr and RNCO

2. RCONHBr and RNCO

3. RNH-Br and RCONHBr 

4. RCON${\mathrm{Br}}_2$

\(CH_3CHO+HCN\rightarrow CH_3CH(OH)CN\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\downarrow{\bf{H.OH}}\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~CH_3CH(OH)COOH~\)

1. 100 % R-isomer

2. 100% S-isomer

3. 50% R + 50% S-isomer

4. 20% R + 80% S-isomer

In a set of the given reactions, acetic acid yielded a product C.

\(\mathrm{CH_3COOH+PCl_5\rightarrow A\xrightarrow[Anh.AlCl_3]{C_6H_6}B\xrightarrow[ether]{C_2H_5MgBr}C}\)
Product C would be:

1.	CH3CH(OH)C2H5
2.	CH3COC6H5
3.	CH3CH(OH)C6H5
4.

When m-chlorobenzaldehyde is treated with 50% KOH solution, the product(s) obtained is (are):

1.
2.
3.
4.

A and B in the following reactions are:

1.
2.
3.
4.

Product 'P' in the above reaction is: 

1.		2.
3.		4.

In the following reaction, product 'P' is:

1. RCH₂OH

2. RCOOH

3. RCHO

4. RCH₃

The product P is:

1.		2.
3.		4.

Clemmensen reduction reaction is:

1.
2.	\(C_6H_5-CO-CH_3 + NH_2NH_2 \xrightarrow{C_2H_5ONa}\\ C_6H_5CH_2CH_3\)
3.	\(CH_3COCH_3 + 4HI \xrightarrow{\text{Red. P}} CH_3CH_2CH_3\)
4.	All of the above

Which one among the given options, can be oxidized to produce a carbonyl compound?

1. o-Nitrophenol

2. Aniline

3. 2-Methyl-2-hydroxypropane

4. 2-Hydroxy propane