The most acidic compound among the following is:

1.    2.  
3.   4.

Subtopic:  Phenols: Preparation & Properties |
 88%
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NEET - 2020
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Identify Z in the following reaction:

\(CH_3CH_2CH=CH_2 \xrightarrow[H_2O,\ H_2O_2,\ OH^-]{B_2H_6} Z \)

1. \(CH_3CH_2CH_2CH_2OH\) 2. \(CH_3CH_2 \ C \ HCH_3 \\~~~~~~~~~~~~~~~~~~| \\~~~~~~~~~~~~~~~~OH\)
3. \(CH_3CH_2CH_2CHO \) 4. \(CH_3CH_2CH_2CH_3 \)
Subtopic:  Alcohols: Preparation & Properties |
 80%
From NCERT
NEET - 2020
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Upon dehydration, the below mentioned compound will not give:

1.  2.  
3.    4.  
Subtopic:  Mechanism of Dehydration, Methanol & Ethanol |
 74%
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An appropriate set of reactants for the preparation of 1-methoxy-4-nitrobenzene is/are : 
 

1.
2.
3.
4.

Subtopic:  Electrophilic Substitution Reactions, Uses of Phenols |
 78%
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Potassium permanganate reagent is used for -
1. Oxidation of primary alcohol to carboxylic acid.
2. Oxidation of primary alcohol to aldehyde.
3. Bromination of phenol to 2,4,6-tribromophenol.
4. Dehydration of propan-2-ol to propene.

Subtopic:  Mechanism of Dehydration, Methanol & Ethanol | Phenols: Preparation & Properties |
 85%
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Propanol has a higher boiling point than that of butane because -

1. Butane undergoes intermolecular ionic bonding

2. Propanol undergoes intermolecular H-bonding

3. Propanol undergoes intramolecular hydrogen bonding

4. Butane undergoes intermolecular H-bonding

Subtopic:  Alcohols: Preparation & Properties |
 84%
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Preparation of ethers by 2 or 3-degree alcohols in an acidic medium is not a suitable method because:

1. In case of secondary or tertiary alcohols, ketone is obtained as a product.
2. In case of secondary or tertiary alcohols, aldehyde is obtained as a product.
3. In case of secondary or tertiary alcohols, alkene is obtained as a product.
4. In case of primary alcohols, alkene is obtained as a product.
Subtopic:  Ethers: Preparation & Properties, Uses |
 72%
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Select the correct option based on statements below:

Assertion (A): p-Nitrophenol is more acidic than phenol.
Reason (R): Nitro group helps in the stabilization of the phenoxide ion by dispersal of negative charge due to resonance.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Alcohols: Preparation & Properties |
 84%
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Match the items of Column I with items of Column II.

Column l 

Column ll 

A.

Reimer-Tiemann reaction 

1.

Conversion of phenol to o-hydroxysalicylic aid 

B.

Kolbe's reaction 

2.

Heated copper at 573K

C.

Conversion of 2° alcohol to a ketone 

3.

Reaction of an alkyl halide
with sodium alkoxide 

D.

Williamson's synthesis 

4.

Conversion of phenol to salicylaldehyde

Codes

A B C D
1. 2 3 4 1
2. 3 4 1 2
3. 1 4 3 2
4. 4 1 2 3
Subtopic:  Ethers: Preparation & Properties, Uses |
 90%
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Match the starting material in Column I with the products formed (Column II) in the reaction with HI.

Column I

Column II

A.  CH3-O-CH3 1.  
B.   2.  
C.   3.  
D.    4.  CH3-OH+CH3I
5.  
 
A B C D
1. 2 3 4 1
2. 3 1 5 2
3. 5 4 3 2
4. 4 5 2 1
Subtopic:  Ethers: Preparation & Properties, Uses |
 91%
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