For a reaction, 2A + B → C + D, the following observations were recorded:

Experiment	[A]/mol L-1	[B]/mol L-1	Initial rate of formation of D/mol L-1 min-1
I	0.1	0.1	6.0 x 10-3
II	0.3	0.2	7.2 x 10-2
III	0.3	0.4	2.88 x 10-1
IV	0.4	0.1	2.40 x 10-2

The rate law applicable to the above mentioned reaction would be:

1. Rate = k[A]²[B]³

2. Rate = k[A][B]²

3. Rate = k[A]²[B]  

4. Rate = k[A][B]  

During a nuclear explosion, one of the products is ⁹⁰Sr with a half-life of 28.1 years. If 1µg of ⁹⁰Sr was absorbed in the bones of a newly born baby instead of calcium, the amount of ⁹⁰Sr that will remain after 10 years in the now grown up child would be -

(Given ,antilog(0.108)=1.28)

1. 0.227 µg 

2. 0.781 µg 

3. 7.81 µg 

4. 2.27 µg 

$1.$ $6.67$ $\times {10}^{-2}$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$ ${\mathrm{s}}^{-1}$
$2.$ $2.67$ $\times$ ${10}^{-4}$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$ ${\mathrm{s}}^{-1}$ $$
$3.$ $4.67$ $\times$ ${10}^{-3}$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$ ${\mathrm{s}}^{-1}$
$4.$ $4.27$ $\times$ ${10}^3$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$ ${\mathrm{s}}^{-1}$

The rate equation of a reaction is expressed as, Rate = \(k(P_{CH_{3}OCH_{3}})^{\frac{3}{2}}\)

(Unit of rate = bar min^-1)

The units of the rate constant will be:

1. bar^1/2 min    
2. bar² min^-1    
3. bar^-1min^-2  
4. bar^-1/2min^-1

The decomposition of NH₃ on a platinum surface is a zero-order reaction. The rates of production of N₂ and H₂
 will be respectively:
(given ; k = 2.5 × 10^–4 mol^–1 L s^–1 ) 

1. 2.5 x 10^-4 mol L^-1 s^-1 and 5.5 x 10^-4 mol L^-1 s^-1

2. 2.5 x 10^-4 mol L^-1 s^-1 and 7.5 x 10^-4 mol L^-1 s^-1

3. 1.5 x 10^-4 mol L^-1 s^-1 and 4.5 x 10^-4 mol L^-1 s^-1

4. 0.5 x 10^-4 mol L^-1 s^-1 and 3.5 x 10^-4 mol L^-1 s^-1

If at a given instant, for the reaction 2N₂O₅ → 4NO₂ + O₂ rate and rate constant are 1.02 × 10^-4  and 3.4 × 10^-5 sec ^-1 respectively, then the concentration of ${\mathrm{N}}_2{\mathrm{O}}_5$ at that time will be: 

1. 1.732 mol L⁻¹

2. 3.0 mol L⁻¹

3. $1.02$ $\times$ ${10}^{-4}$ mol L⁻¹

4. $3.4$ $\times$ ${10}^5$ mol L⁻¹

Select the correct option based on statements below:

Match the items in Column I and Column II:

Codes

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