- 1(current)
Q. No.At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic: Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
59%
From NCERT
NEET - 2016
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NEET 2023 - Target Batch - Aryan Raj Singh
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If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapor pressure to 80 %, the molar mass (in g mol–1) of the solute is -
[Molar mass of n-octane is 114 g mol–1]
| 1. | 40 | 2. | 60 |
| 3. | 80 | 4. | 20 |
Subtopic: Relative Lowering of Vapour Pressure |
60%
From NCERT
NEET - 2020
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NEET 2023 - Target Batch - Aryan Raj Singh
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To view explanation, please take trial in the course.
NEET 2023 - Target Batch - Aryan Raj Singh
- 1(current)
Q. No.
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