Choose a false statement among the following:

1.  Raoult's law states that the vapour pressure of a component over a solution is proportional to its mole fraction.
2.  The osmotic pressure (\(\pi\)) of a solution is given by the equation \(\pi\)=MRT, where M is the molarity of the solution.
3.  The correct order of osmotic pressure for 0.10 M aqueous solution of each compound is BaCl2 > KCl > CH3COOH > sucrose.
4.  Two sucrose solutions of the same molarity prepared in different solvents will have the same depression in the freezing point. 

Subtopic:  Depression of Freezing Point | Raoult's Law |
 73%
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Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2at 298 K are 200 mm Hg and 415 mm Hg respectively. The vapour pressure of the solution prepared by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at 298 K is 347.9 mm Hg.

The mole fractions of each component, that is, CHCl
3 and CH2Cl2 in vapour phase are respectively-

0.82; 0.18
2. 0.16; 0.84
3. 0.18; 0.82
4. 0.84; 0.16

 
Subtopic:  Raoult's Law |
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The osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C is-

1. 37 Pa
2. 35 Pa
3. 31 pa
4. 41 Pa
Subtopic:  Osmosis & Osmotic Pressure |
 58%
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If A (volatile solute) and B (volatile solvent) form an azeotropic mixture then the correct statement regarding the above azeotropic mixture will be - 
 
1. Mole fraction of A in the vapour phase is more than the mole fraction of A or B in liquid phase 
2. Mole fraction of A or B in the vapour phase is more than the mole fraction of A or B in liquid phase 
3. Mole fraction of A or B in the vapour phase is same as the mole fraction of A or B in liquid phase
4. Mole fraction of A and B in the vapour phase is less than the mole fraction of A or B in liquid phase 
Subtopic:  Azeotrope |
 65%
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 Acetic acid dimerises in benzene . The value of Van't Hoff factor (i) for the dimerisation of acetic acid is 0.7.  The percetage dimerisation of acetic acid will be-
1. 30% 
2. 60% 
3. 70% 
4. 90%  
Subtopic:  Van’t Hoff Factor |
 65%
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On mixing, heptane, and octane form an ideal solution at 373 K, the vapor pressures of the two liquid components (Heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25.0 g of heptane and 35 g of octane will be:
(molar mass of heptane = 100 g mol−1 and of octane =114 g 1 mol−1)

1. 144.5 kPa

2. 72.0 kPa

3. 36.1 kPa

4. 96.2 kPa

Subtopic:  Raoult's Law |
 75%
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The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it to the nearest integer is-
1. 44%
2. 49 %
3. 47 %
4. 41 %

Subtopic:  Concentration Terms & Henry's Law |
 62%
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45 g of ethylene glycol (C2H6O2) is mixed with 600 g of water. The freezing point of the solution is -

1. 268.15 K
2. 270.95 K
3. 272.75 K
4. 267.15 K

Subtopic:  Depression of Freezing Point |
 64%
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The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. The molar mass of the solute is-

Kb for benzene is 2.53 K kg mol–1

1. 55 g mol–1
2. 64 g mol–1
3. 58 g mol–1  
4.
68 g mol–1

Subtopic:  Elevation of Boiling Point |
 64%
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If N2 gas is bubbled through water at 293 K, how many millimoles of N2 gas would dissolve in 1 litre of water?
(
Partial pressure of nitrogen = 0.987 bar, Henry’s law constant for N2 at 293 K = 76.48 kbar).

1. 0.716 mmol

2. 0.616 mmol

3. 0.726 mmol

4. 0.516 mmol

Subtopic:  Concentration Terms & Henry's Law |
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