1.00 g of non-electrolyte solute (molar mass 250 g mol-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 mol-1 kg K, the freezing point of benzene will be lowered by:

1. 0.4 K

2. 0.3 K

3. 0.5 K

4. 0.2 K

Subtopic:  Elevation of Boiling Point |
 84%
From NCERT
AIPMT - 2006
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A solution that has the highest boiling point among the following is -

1. 1.0 M NaOH

2. 1.0 M Na2SO4 

3. 1.0 M NH4NO3

4. 1.0 M KNO3

Subtopic:  Elevation of Boiling Point |
 82%
From NCERT
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The unit of Ebullioscopic constant is:

1. K kg mol-1 or K (molality)-1

2. mol kg K-1 or K-1 (molality)

3. kg mol-1 K-1 or K-1 (molality)-1

4. K mol kg-1 or K (molality)

Subtopic:  Elevation of Boiling Point |
 78%
From NCERT
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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
 59%
From NCERT
NEET - 2016
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Aluminium phosphate is 100 % ionized in 0.01 m aqueous solution. Hence, Tb/kb is-

1. 0.01 m 2. 0.015 m
3. 0.0175 m 4. 0.02 m
Subtopic:  Elevation of Boiling Point |
 59%
From NCERT
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Match the laws given in Column I with expressions given in Column II.

Column I Column II
A. Raoult’s law 1. π = CRT
B. Osmotic pressure  2. ΔTf=Kfm
C. Elevation of boiling point 3. p=x1p10 +x2p20
D. Depression in freezing point 4. ΔTb=Kbm

Codes

A B C D
1. 2 3 4 1
2. 1 2 3 4
3. 1 4 3 2
4. 3 1 4 2
Subtopic:  Elevation of Boiling Point | Depression of Freezing Point |
 93%
From NCERT
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