The correct hybridization states of carbon atoms in the following compound are -     C1H2=C2H-C3N
 

1. C1= sp , C2= sp, C3= sp2 2. C1= sp2 , C2= sp,  C 3 = sp3
3. C1= sp2 , C2= sp,  C 3 = sp 4. C1= sp3 , C2= sp,  C 3 = sp3
Subtopic:  Hybridisation & Structure of Carbon Compounds |
 91%
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The number of σ and π bonds in the molecule C6H6 are -

1. 6 C – C sigma ( σ C - C )  bonds, 5 C–H sigma ( ( σ C - H )  bonds, and 3 C=C pi ( π C - C ) 
2. 6 C – C sigma ( σ C - C )  bonds, 5 C–H sigma ( ( σ C - H )  bonds, and 2 C=C pi ( π C - C ) 
3. 6 C – C sigma ( σ C - C )  bonds, 6 C–H sigma ( ( σ C - H )  bonds, and 3 C=C pi ( π C - C ) 
4. 6 C – C sigma ( σ C - C )  bonds, 6 C–H sigma ( ( σ C - H )  bonds, and 2 C=C pi ( π C - C ) 

Subtopic:  Hybridisation & Structure of Carbon Compounds |
 87%
From NCERT
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The number of primary carbon atoms in the following compound are:

1. 6 2. 2
3. 4 4. 3
Subtopic:  Hybridisation & Structure of Carbon Compounds |
 86%
From NCERT
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The \(C - H\) bond distance is longer in - 

1. \(C_2H_2\) 2. \(C_2H_4\)
3. \(C_2H_6\) 4. \(C_2H_2Br_2\)
Subtopic:  Hybridisation & Structure of Carbon Compounds |
 77%
From NCERT
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The total number of pi-bond electrons in the following structure are:
1. 4 2. 8
3. 12 4. 16
Subtopic:  Hybridisation & Structure of Carbon Compounds |
 66%
From NCERT
NEET - 2015
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