The arrangement in decreasing order of stability of CH3C2H5,(CH3)2CH and (CH3)3 C free radicals is-

1. CH3C2H5 > (CH3)2CH > (CH3)3 C  

2. (CH3)3 C > (CH3)2CH > C2H5CH3

3. C2H5CH3 > (CH3)2CH > (CH3)3 C

4. (CH3)3 C > (CH3)2CH >  CH3  > C2H5 

Subtopic:  Reaction Intermediates ; Preparation & Properties |
 84%
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The most stable carbocation among the following is:

1. 2.
3. 4.
Subtopic:  Reaction Intermediates ; Preparation & Properties |
 76%
From NCERT
To view explanation, please take trial in the course.
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To view explanation, please take trial in the course.
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