Geometrical isomerism can be shown by:

1.
2.
3.
4.

Geometrical isomerism is caused by-

1. Restricted rotation around C=C bond.

2. The presence of one asymmetric carbon atom.

3. The different groups attached to the same functional group.

4. None of the above.

The compounds that show geometrical isomerism among the following are:

a. 2-Butene

b. Propene

c. 1-Phenylpropene

d. 2-Methylbut-2-ene

1. a, b

2. c, d

3. a, b, c

4. a, c

The chiral compound among the following is:

But-2-ene exhibits cis-trans isomerism due to-

1. Rotation around ${\mathrm{C}}_3-{\mathrm{C}}_4$ sigma bond

2. Rotation around  ${\mathrm{C}}_1-{\mathrm{C}}_2$ bond

3. Restricted rotation around C=C bond

4. Rotation around  ${\mathrm{C}}_2-{\mathrm{C}}_3$ double bond

 The structure of diphenylmethane is given below:

The number of  structural isomers possible when one of the hydrogen atom is replaced by a chlorine atom are :

The optically active compound among the following is-

1. Butane

2. 2-Methyl pentane

3. 4-Methyl pentane

4. 3-Methyl hexane

The maximum number of stereoisomers possible for 3-hydroxy-2-methyl butanoic acid is/are :

1. 1               

2. 2

3. 3               

4. 4

Glucose and fructose are-

The optically active compound among the following is-