The IUPAC name of the above-mentioned compound is - 

1. (N-Bromo)-3-methyl-2-oxobutanamide

2. (N-Bromo)-2-oxo-4-methylbutanamide

3. (N-Bromo)-1,2-dioxo-3-methylbutanamine carboxamide

4. (N-Bromo)-1-oxo-2-methylpropane

Subtopic:  Nomenclature |
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The colour of the solution that gets formed by mixing sodium nitroprusside to an alkaline solution of sulfide ions, is-

1. Red 2. Blue
3. Brown 4. Purple

Subtopic:  Quantitative Analysis of Organic Compounds |
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In Kjeldahl's method, the nitrogen present is estimated as-

1. N2 

2. NH3

3. NO2 

4 None of the above

Subtopic:  Quantitative Analysis of Organic Compounds |
 64%
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In Kjeldahl's method of estimation of nitrogen, K2SO4 acts as:

1. An oxidizing agent 2. A catalytic agent
3. A hydrolyzing agent 4. A boiling point elevator
Subtopic:  Qualitative Analysis of Organic Compounds |
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The Prussian blue colour obtained during the test of nitrogen by Lassaigne's test is due to the formation of-

1. Fe4[Fe(CN)6]3 2. Na3[Fe(CN)6]
3. Fe(CN)3  4. Na4[Fe(CN)5NOS]
Subtopic:  Qualitative Analysis of Organic Compounds |
 73%
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Soda extract is prepared by-

1. Fusing soda and mixture of hydrocarbons, and then extracted with water

2. Dissolving NaHCO3 and mixture of hydrocarbons in dil. HCl

3. Boiling Na2COand mixture of hydrocarbons in dil. HCl

4. Boiling Na2COand mixture of hydrocarbons in distilled water

Subtopic:  Qualitative Analysis of Organic Compounds |
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The most stable carbocation among the following is:

1. 2.
3. 4.
Subtopic:  Reaction Intermediates ; Preparation & Properties |
 76%
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The arrangement in decreasing order of stability of CH3C2H5,(CH3)2CH and (CH3)3 C free radicals is-

1. CH3C2H5 > (CH3)2CH > (CH3)3 C  

2. (CH3)3 C > (CH3)2CH > C2H5CH3

3. C2H5CH3 > (CH3)2CH > (CH3)3 C

4. (CH3)3 C > (CH3)2CH >  CH3  > C2H5 

Subtopic:  Reaction Intermediates ; Preparation & Properties |
 84%
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The species that contains only three pairs of electrons among the following is-

1. Carbocation 2. Carbanion
3. Free radical 4. None of the above
Subtopic:  Reaction Intermediates ; Preparation & Properties |
 63%
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The increasing order of +ve I-effect shown by H, CH3, C2H5 and C3H7 is-

1. H < CH3 < C2H5 < C3H7

2. H> CH3 <C2H5 > C3H7

3. H < C2H5 < CH3 <C3H7

4. None of the above

Subtopic:  Electron Displacement Effects |
 82%
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