For the redox reaction,
 a${\mathrm{MnO}}_4^{-}+{\mathrm{bC}}_2{\mathrm{O}}_4^{2-}+{\mathrm{cH}}^{+}\to {\mathrm{dMn}}^{2+}+{\mathrm{eCO}}_2+{\mathrm{fH}}_2\mathrm{O}$
the correct stoichiometric coefficients of the reactants a, b, and c respectively for the balanced equation are: 

1. 16, 5, 2
2. 2, 5, 16
3. 2, 16, 5
4. 5, 16, 2

The change in oxidation number of chlorine when Cl₂ gas reacts with hot and concentrated sodium hydroxide solution is:

1. Zero to +1 and Zero to –5

2. Zero to –1 and Zero to +5

3. Zero to –1 and Zero to +3

4. Zero to +1 and Zero to –3

The reaction that does not represent auto redox or disproportionation is: 

1. ${\mathrm{Cl}}_2+{\mathrm{OH}}^{-}\to {\mathrm{Cl}}^{-}+{\mathrm{ClO}}_3^{-}+{\mathrm{H}}_2\mathrm{O}$

2. $2{\mathrm{H}}_2{\mathrm{O}}_2\to {\mathrm{H}}_2\mathrm{O}+{\mathrm{O}}_2$

3. $2{\mathrm{Cu}}^{+}\to {\mathrm{Cu}}^{2+}+\mathrm{Cu}$

4. ${\left({\mathrm{NH}}_4\right)}_{2}C{r}_2{O}_7\to {\mathrm{N}}_2+{\mathrm{Cr}}_2{\mathrm{O}}_3+4{\mathrm{H}}_2\mathrm{O}$

Balance the following equation and choose the quantity that is the sum of the coefficients of reactants and products :

$...{\mathrm{PtCl}}_4+...{\mathrm{XeF}}_2\to {\mathrm{PtF}}_6+....\mathrm{ClF}+...\mathrm{Xe}$

1. 16

2. 13

3. 18

4. 12

The standard electrode potential (E°) values of  Al³⁺/ Al,  Ag⁺ / Ag, K⁺ / K,  and Cr³⁺ / Cr are –1.66 V, 0.80 V, –2.93 V, & –0.79 V respectively. The correct decreasing order of the reducing power of the metal is:

In the given balanced chemical reaction,

${{}^{}}_{}$
\(\mathrm{IO}_3^{-}+\mathrm{aI}^{-}+\mathrm{bH}^{+} \rightarrow \mathrm{cH}_2 \mathrm{O}+\mathrm{dI}_2\)

The values of a, b, c, and d respectively are-

1. 5, 6, 3, 3

2. 5, 3, 6, 3

3. 3, 5, 3, 6

4. 5, 6, 5, 5

Oxidation number of oxygen in potassium super oxide (KO₂) is-

1. – 2

2. – 1

3. – 1/2

4. – 1/4

 The strongest oxidising agent among the following is -

1. $Br{O}_3^{-}/B{r}^{2+},E^o=+1.50$

2. $F{e}^{3+}/F{e}^{2+},E^o=+0.76$

3. $Mn{O}_4^{-}/M{n}^{2+},E^o=+1.52$

4. $C{r}_2{O}_7^{2-}/C{r}^{3+},E^o=+1.33$

The oxidation number of S in H₂S₂O₈ is:

1. + 2

2. + 4

3. + 6

4. + 7

In the following reaction

Al + Fe₃O₄ $\to$Al₂O₃ + Fe

The total number of electrons transferred will be-

1. 6

2. 8

3. 8/3

4. 24