Consider the following equation:
Cr2O72–(aq) + 3SO32– (aq)+ 8H+(aq) → A + B +4H2O(l)
The product A and B are respectively-
1. 2Cr2+; 3SO2
2. 2Cr+; S2O7 2-
3. 2Cr3+; 3SO4 2-
4. 2Cr3+; 3HSO42-
aMnO4–(aq) + bBr–(aq) + cH2O(l) → dMnO2(s) + eBrO3– (aq) + fOH–(aq)
The value of c, d and f in the above mentioned reaction are respectively-
1. c=1; d=2; f=2
2. c=2; d=1; f=2
3. c=2; d=2; f=1
d. c=1; d=1; f=1
Permanganate(VII) ion, MnO4– in basic solution oxidizes iodide ion, I– to produce molecular iodine (I2) and manganese (IV) oxide (MnO2). The reaction is as follows:
aI–(aq) + bMnO4–(aq) + cH2O(l) → dI2(s) + eMnO2(s) + fOH–(aq)
The value of b, d and f are-
1. b=2; d=3; f=8
2. b=1; d=3; f=8
3. b=3; d=8; f=2
4. b=8; d=3; f=2