The correct relation between dissociation constants of a di-basic acid is:

1. $K{a}_1=K{a}_2$

2. $K{a}_1>K{a}_2$

3. $K{a}_1<K{a}_2$

4. $K{a}_1=\frac{1}{K{a}_2}$

For any reversible reaction, if we increase the concentration of the reactants, the effect on equilibrium constant will:
1. Depend on the amount of concentration
2. Remain unchanged
3. Decrease
4. Increase

Equilibrium constants K₁ and K₂ for the following equilibria

$\begin{array}{l}\mathrm{NO}\left(\mathrm{g}\right)+\frac{1}{2}{\mathrm{O}}_2\stackrel{{\mathrm{K}}_1}{⟶}{\mathrm{NO}}_2\left(\mathrm{g}\right)\text{ and }\\ 2{\mathrm{NO}}_2\left(\mathrm{g}\right)\stackrel{{\mathrm{K}}_2}{\rightleftharpoons }2\mathrm{NO}\left(\mathrm{g}\right)+{\mathrm{O}}_2\left(\mathrm{g}\right)\end{array}$

are related as:

1. ${\mathrm{K}}_2=\frac{1}{{\mathrm{K}}_1}$

2. ${\mathrm{K}}_2=\frac{{\mathrm{K}}_1}{2}$

3. ${\mathrm{K}}_2=\frac{1}{{\mathrm{K}}_1^2}$

4. ${\mathrm{K}}_2={\mathrm{K}}_1^2$

Conjugate acid of NH₂^– is:

1. NH₄OH

2. NH₄⁺

3. \(NH_{2}^{-}\)

4. NH₃

Incorrect statement about pH and H⁺ is: 
 

At 25 ºC, the dissociation constant of a base, BOH, is 1.0 × 10^–12. The concentration of hydroxyl ions in 0.01M aqueous solution of the base would be:

$\mathrm{If\; A}$ $+$ $B$ $\leftrightharpoons$ $C$ $+$ $D$ $Cons\tan t$ $=$ $K_1$
$E$ $+$ $F$ $\rightleftharpoons$ $G$ $+$ $H$ $Cons\tan t$ $=$ $K_2$

then C + D + E + F ⇒ product. The constant of reaction will be:

1.  $\frac{K_1}{K_2}$

2.  $\frac{K_2}{K1}$

3. $K_1{K}_2$

4. None of these 

The fertilizer which makes the soil acidic is:

1. ${\left(N{H}_4\right)}_{2}S{O}_4$

2.  Super phosphate of lime .

3. $C{H}_{3}COONa$

4. $Ca{\left(N{O}_3\right)}_2$

What is the correct relationship between the pHs of isomolar solutions of sodium oxide (pH₁), sodium sulphide (pH₂), sodium selenide (pH₃), and sodium telluride (pH₄)?

1. ${\mathrm{pH}}_1<{\mathrm{pH}}_2<{\mathrm{pH}}_3<{\mathrm{pH}}_4$

2. ${\mathrm{pH}}_1>{\mathrm{pH}}_2>{\mathrm{pH}}_3>{\mathrm{pH}}_4$

3. ${\mathrm{pH}}_1<{\mathrm{pH}}_2<{\mathrm{pH}}_3\approx {\mathrm{pH}}_4$

4. ${\mathrm{pH}}_1>{\mathrm{pH}}_2\approx {\mathrm{pH}}_3>{\mathrm{pH}}_4$

H₂S gas when passed through a solution of cations containing HCl precipitates the cations of second group of qualitative analysis but not those belonging to the fourth group. It is because: