Q. No.Match the coordination number and type of hybridization with the distribution of hybrid orbitals in space based on Valence bond theory.
Coordination number and type of hybridisation
Distribution of hybrid orbitals in space
(a) 4, sp3
(i) Trigonal bipyramidal
(b) 4, dsp2
(ii) Octahedral
(c) 5, sp3d
(iii) Tetrahedral
(d) 6, d2sp3
(iv) Square planar
(a)
(b)
(c)
(d)
1.
(ii)
(iii)
(iv)
(i)
2.
(iii)
(iv)
(i)
(ii)
3.
(iv)
(i)
(ii)
(iii)
4.
(iii)
(i)
(iv)
(ii)
Among the following, the correct statements about
| a. |
The hybridisation of the central atom is sp3 |
| b. |
Its resonance structure has one C-O single bond and two C=O double bonds |
| c. |
The average formal charge on each oxygen atom is 0.67 units |
| d. |
All C-O bond lengths are equal |
Choose the correct option
1. (a), (b)
2. (b), (c)
3. (c), (d)
4. (b), (d)
The incorrect statements among the following are-
| (a) | NaCl being an ionic compound is a good conductor of electricity in the solid-state |
| (b) | In canonical structure, there is a difference in the arrangement of atoms |
| (c) | Hybrid orbitals form stronger bonds than pure orbitals |
| (d) | VSEPR theory can explain the square planar geometry of XeF4 |
| 1. | (a) and (b) only | 2. | (b) and (c) only |
| 3. | (c) and (d) only | 4. | (b) and (d) only |
Given below are two statements:
| Assertion (A): | Among the two O-H bonds in H2O molecule, the energy required to break the first O-H bond and the other O-H bond is the same. |
| Reason (R): | The electronic environment around oxygen is the same even after the breakage of one O-H bond. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | Both (A) and (R) are False. |
Given below are two statements:
| Assertion (A): | Though the central atom of both NH3 and H2O molecules are sp3 hybridised, yet H-N-H bond angle is greater than that of H-O-H. |
| Reason (R): | This is because nitrogen atom has one lone pair and oxygen atom has two lone pairs. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Given below are two statements:
| Assertion (A): | Sodium chloride formed by the action of chlorine gas on sodium metal is a stable compound. |
| Reason (R): | This is because sodium and chloride ions acquire octet in sodium chloride formation. |
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true but (R) is false. |
| 4. | (A) is false but (R) is true. |
Match the shape of molecules in Column I with the type of hybridization in Column II.
|
Column I |
Column II |
|
A. Tetrahedral |
1. sp2 |
|
B. Trigonal |
2. sp |
|
C. Linear |
3. sp3 |
Codes
| Options: | A | B | C |
| 1. | 3 | 1 | 2 |
| 2. | 1 | 2 | 3 |
| 3. | 5 | 4 | 3 |
| 4. | 4 | 5 | 3 |
Match the items given in Column I with examples given in Column II.
|
Column I |
Column II |
|
A. Hydrogen bond |
1. C |
|
B. Resonance |
2. LiF |
|
C. Ionic solid |
3. H2 |
|
D. Covalent solid |
4. HF |
|
5. O3 |
Codes
| Options: | A | B | C | D |
| 1. | 2 | 3 | 4 | 1 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 2 | 1 |
Match the species in Column I with the bond order in Column II.
|
Column I |
Column II |
|
A. NO |
1. 1.5 |
|
B. CO |
2. 2.0 |
|
C. O2- |
3. 2.5 |
|
D. O2 |
4. 3.0 |
Codes
| Options: | A | B | C | D |
| 1. | 3 | 4 | 1 | 2 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
Match the species in Column I with the shape in Column II.
|
Column I |
Column II |
|
A. H3O+ |
1. Linear |
|
B. HCCH |
2. Angular |
|
C. ClO2- |
3. Tetrahedral |
|
D. NH4+ |
4. Trigonal bipyramidal |
|
5. Pyramidal |
Codes
| Options: | A | B | C | D |
| 1. | 5 | 1 | 2 | 3 |
| 2. | 1 | 2 | 3 | 5 |
| 3. | 5 | 4 | 3 | 2 |
| 4. | 4 | 5 | 3 | 2 |
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