An electronic configuration representing an atom in the excited state is: 

$1.$ $1{\mathrm{s}}^2,2{\mathrm{s}}^{2}2{\mathrm{p}}^1$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$
$2.$ $1{\mathrm{s}}^2,2{\mathrm{s}}^{2}2{\mathrm{p}}^2$
$3.$ $1{\mathrm{s}}^2,2{\mathrm{s}}^{2}2{\mathrm{p}}^2,3{\mathrm{s}}^1$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$ $$
$4.$ $1{\mathrm{s}}^2,2{\mathrm{s}}^{2}2{\mathrm{p}}^5$

Consider the following sets of quantum numbers:

              n         l         m         s

(i)         3         0         0          +1/2

(ii)        2         2         1          +1/2

(iii)       4         3        -2           -1/2

(iv)       1         0        -1           -1/2

(v)        3         2         3           +1/2

Which of the following sets of quantum numbers is not possible?

1. ii, iii and iv                             

2. i, ii, iii and iv

3. ii, iv and v                               

4. i and iii

If uncertainty in position and momentum are both equal, then uncertainty in velocity will be: 

1. $\frac{1}{2\mathrm{m}}\sqrt{\frac{\mathrm{h}}{\mathrm{\pi }}}$

2. $\sqrt{\frac{\mathrm{h}}{2\mathrm{\pi }}}$

3. $\frac{1}{\mathrm{m}}\sqrt{\frac{\mathrm{h}}{\mathrm{\pi }}}$

4. $\frac{\mathrm{h}}{\mathrm{\pi }}$

The group number and electronic configuration of  element Z =114 is: 

1. Halogen family, [Rn]5f¹⁴6d¹⁰7s²7p⁵

2. Carbon family, [Rn]5f¹⁴6d¹⁰7s²7p²

3. Oxygen family, [Rn]5f¹⁴6d¹⁰7s²7p⁴

4. Nitrogen family, [Rn]5f¹⁴6d¹⁰7s²7p⁶

 When an electron jumps from n=5 to n=1 in a hydrogen atom, the number of spectral lines obtained is 

Incorrect statement among the following is: 

The incorrect statement among the following is:

1.	Total orbital angular momentum of an electron in 's' orbital is equal to zero.
2.	An orbital is designated by three quantum numbers, while an electron in an atom is designated by four quantum numbers.
3.	The electronic configuration of N atom is
4.	The value of m for dz2 is zero.

The correct set of four quantum numbers for the valence electron of a rubidium atom (Z =37) is: 

The incorrect set of quantum numbers among the following is:

1. n= 4, l= 0, m= 0, s= -1/2
2. n= 5, l= 3, m= 0, s= +1/2
3. n= 3, l= 2, m= -3, s= -1/2
4. n= 3, l= 2, m= 2, s= -1/2

The correct order of the total number of nodes of atomic orbitals is: 

1.  4f > 6s > 5d

2.  6s > 5d > 4f

3.  4f > 5d > 6s

4.  5d > 4f > 6s