The number of significant figures in the following numbers is:
 

(I). 161 cm
(II). 0.0161
(III). 1.61


1. 3, 3, 3
2. 3, 4, 3
3. 3, 2, 3
4. 3, 4, 4

Subtopic:  Introduction |
 72%
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AIPMT - 1998
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The mass of CaCO3 required to react completely with 25 mL of 0.75 M HCl according to the given reaction would be:

CaCO3(s) + HCl(aq) ➡ CaCl2(aq) + CO2(g) + H2O(l) 

1. 0.36 g

2. 0.09 g

3. 0.96 g

4. 0.66 g

Subtopic:  Concentration Based Problem | Equation Based Problem |
 61%
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One mole of oxygen gas at STP is equal to:

(a) 6 .022× 1023 molecules of oxygen
(b) 6.022 × 1023 atoms of oxygen
(c) 16 g of oxygen molecule
(d) 32 g of oxygen

1. (a) and (b)

2. (a) and (c)

3. (a) and (d)

4. (c) and (d)

Subtopic:  Moles, Atoms & Electrons |
 75%
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Sulphuric acid reacts with sodium hydroxide as follows

H2SO4+2NaOHNa2SO4+2H2O

When 1L of 0.1 M sulphuric acid solution is allowed to react with 1 L of 0.1 M sodium hydroxide solution, the amount of sodium sulphate formed and its molarity in the solution obtained are respectively-

1. 0.1 M, 7.10 g

2. 7.10 g, 0.025 M

3. 0.025 M, 3.55 g

4. 3.55 g, 0.25 M

Subtopic:  Concentration Based Problem |
 54%
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The correct match is:
List I List II
a. Micro i. 10-15 m
b. Mega ii. 10-6 m
c. Giga iii. 106 m
d. Femto iv. 109 m
 
a b c d
1. i iv iii ii
2. iii iv ii i
3. ii iii iv i
4. i iii iv ii
Subtopic:  Introduction |
 86%
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Percentage of C, H & N of a compound is given as follows:
C=40%, H=13.33%, N=46.67%
The empirical formula of the compound will be:

1. CH2N

2. C2H4N

3. CH4N

4. CH3N

Subtopic:  Empirical & Molecular Formula |
 76%
From NCERT
AIPMT - 1998
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When 50.0 kg of nitrogen gas (N2) and 10.0 kg of hydrogen gas (H2) are combined, what is the quantity of ammonia gas (NH3) produced?

1. 33.0 ×103 mol

2. 56.1×103 g

3. 6.5 ×103 g

4. None of the above

Subtopic:  Limiting Reagent |
 58%
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A solution is prepared by adding 2 g of substance A to 18 g of water. The mass percent of the solute is-

1. 20%

2. 10%

3. 15%

4. 18%

Subtopic:  Concentration Based Problem |
 86%
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The NaNO3 weighed out to make 50 mL of an aqueous solution containing 70.0 mg Na+ per mL is- 

(Rounded off to the nearest integer) [Given: Atomic weight in g mol–1 – Na: 23; N: 14; O: 16]

1. 13 g

2. 26 g

3. 18 g

4. 22 g

Subtopic:  Concentration Based Problem |
 62%
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An aqueous solution of urea containing 18 g of urea in 1500 cm3 of the solution has a density of 1.052 g/cm3. If the molecular weight of urea is 60, then the molality of the solution is-
1. 0.2
2. 0.192
3. 0.064
4. 1.2

Subtopic:  Concentration Based Problem |
 70%
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