1 g of magnesium is burnt with 0.56g of oxygen in a closed vessel. The left-out reactant and its quantity are

(At. weight of Mg = 24, O=16)

1. Mg, 0.16g 2. O2, 0.16g
3. Mg, 0.44g 4. O2, 0.28g

Subtopic:  Equation Based Problem |
 51%
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In the reaction, 4NH3(g)+ 5O2(g) 4NO(g) +6H2O(l)

When 1 mole of ammonia and 1 mole of O2  reacts to completion, then:

1. 1.0 mole of H2O is produced. 
2. 1.0 mole of NO will be produced.
3. All the oxygen will be consumed.
4. All the ammonia will be consumed.

Subtopic:  Equation Based Problem |
 68%
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An element X has the following isotopic composition,

200X : 90%, 199X : 8.0%, 202X : 2.0%

The weighted average atomic mass of the naturally occurring element X is closest to: 

1. 201 u 2. 202 u
3. 199 u 4. 200 u
Subtopic:  Moles, Atoms & Electrons |
 62%
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When 100 mL of PH3 is decomposed, it produces phosphorus and hydrogen. The change in volume is:

1. 50  mL increase. 2. 500 mL decrease.
3. 900 mL decrease. 4. None of the above.

Subtopic:  Equation Based Problem |
 56%
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The total molarity of all the ions present in  0.1 M of CuSO4 and 0.1 M of Al2(SO4)3 solution is:

1. 0.2M

2. 0.7M

3. 0.8M

4. 1.2M

Subtopic:  Concentration Based Problem |
 63%
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The mole fraction of the solute in a 1.00 molal aqueous solution is: 

1. 0.00177 2. 0.0344
3. 0.0177 4. 0.1770
Subtopic:  Concentration Based Problem |
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Consider the given reaction, 2SO2 + O2 2SO

6.4 g SO2 and 3.2 g O2 to form SO3 . The mass of SO3 formed is:  

1. 32 g
2. 16 g
3. 8 g
4. 4 g

Subtopic:  Equation Based Problem |
 67%
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The molality of a 20% (by mass) CaCO3 solution is : 
(Given: Density of solution is 1.2 gm/ml)

1. 1.25 m 2. 2.5 m
3. 2.08 m 4. 1.5 m
Subtopic:  Concentration Based Problem |
 66%
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What is the ratio of the number of atoms in 2.2 g of CO2 and in 1.7 g of NH3?

1. 1/2 2. 1/8
3. 3/8 4. 3/2
Subtopic:  Moles, Atoms & Electrons |
 56%
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An organic substance containing C, H, and O gave the following percentage composition :

C = 40.687%, H = 5.085% and O = 54.228%. The vapour density of this organic substance is 59.

The molecular formula of the compound will be:

1. C4H6O4

2. C4H6O2

3. C4H4O2

4. None of the above

Subtopic:  Moles, Atoms & Electrons |
 70%
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