In order to find out the different types of gametes produced by a pea plant having the genotype AaBb, it should be crossed to a plant with the genotype:
1. AaBb
2. aabb
3. AABB
4. aaBB
Which of the following is not a hereditary disease:
1. Haemophilia
2. Cretinism
3. Cystic fibrosis
4. Thalasasemia
Haemophilia is more commonly seen in human males than in human females because:
1. | This disease is due to a Y-linked recessive mutation |
2. | This disease is due to an X-linked recessive mutation |
3. | This disease is due to an X-linked dominant mutation |
4. | A greater proportion of girls die in infancy |
A woman with 47 chromosomes, due to three copies of chromosome 21, is characterized by:
1. | Turner syndrome | 2. | Down syndrome |
3. | Superfemaleness | 4. | Triploidy |
A man and a woman, who do not show any apparent signs of a certain inherited disease, have seven children (2 daughters and 5 sons). Three of the sons suffer from the given disease but none of the daughters are affected. Which of the following mode of inheritance might be the reason for this disease?
1. Sex-limited recessive
2. Autosomal dominant
3. Sex-linked recessive
4. Sex-linked dominant
If a female having gene for haemophilia and colour-blindness on one X-chromosome marries a normal male, then what are the chances in their offspring?
1. 50% sons diseased and 50% normal
2. All normal offspring
3. 100% daughters are carrier
4. 100% sons diseased
Reason for trisomy in Down's syndrome is:
1. Non-disjunction during sperm formation
2. Non-disjunction during egg formation
3. Non-disjunction at the time of egg or sperm formation
4. Addition of one extra chromosome during mitosis
Mental retardation in man occurs due to:
1. Loss of one X chromosome
2. Addition of one X chromosome
3. Slight growth in Y
4. Overgrowth in Y
ABO blood group has:
1. Two codominant and one recessive allele
2. Two codominant and two recessive allele
3. Two incompletely dominant genes
4. Two pseudo alleles
A normal woman, whose father was colour-blind is married to a normal man. The sons would be:
1. 50% colour-blind
2. All normal
3. All colour-blind
4. 75 % colour-blind