Q. No.In a marriage between a male with blood group A and a female with blood group B, the progeny had either blood group AB or B. What could be the possible genotype of the parents?
1. IA i (Male) ; IB IB (Female)
2. IA IA (Male) ; IB IB (Female)
3. IA IA (Male) ; IB i (Female)
4. IA i (Male) ; IB i(Female)
In which genetic condition, each cell in the affected person, has three sex chromosomes XXY?
1. Thalassemia
2. Klinefelter's Syndrome
3. Phenylketonuria
4. Turner's Syndrome
Match the items of Column - I with Column - II :
| Column-I | Column-II | ||
| (a) | XX-XO method of sex determination | (i) | Turner's syndrome |
| (b) | XX-XY method of sex Determination | (ii) | Female heterogametic |
| (c) | Karyotype-45 | (iii) | Grasshopper |
| (d) | ZW-ZZ method of Sex Determination | (iv) | Female homogametic |
Select the correct option from the following:
| (a) | (b) | (c) | (d) | |
| 1. | (ii) | (iv) | (i) | (iii) |
| 2. | (i) | (iv) | (ii) | (iii) |
| 3. | (iii) | (iv) | (i) | (ii) |
| 4. | (iv) | (ii) | (i) | (iii) |
What is the genetic disorder in which an individual has an overall masculine development gynaecomastia, and is sterile?
| 1. | Down's syndrome | 2. | Turner's syndrome |
| 3. | Klinefelter's syndrome | 4. | Edward syndrome |
Select the incorrect statement:
| 1. | Human males have one of their sex-chromosome much shorter than the other. |
| 2. | Male fruit fly is heterogametic. |
| 3. | In male grasshoppers, 50% of sperms have no sex chromosome. |
| 4. | In domesticated fowls, the sex of progeny depends on the type of sperm rather than the egg. |
In Antirrhinum (Snapdragon), a red flower was crossed with a white flower and in F1 generation, pink flowers were obtained. When pink flowers were selfed, the F2 generation showed white, red, and pink flowers. Choose the incorrect statement from the following:
| 1. | Law of Segregation does not apply in this experiment. |
| 2. | This experiment does not follow the Principle of Dominance. |
| 3. | The pink colour in F1 is due to incomplete dominance. |
| 4. | Ratio of F2 is 1/4(red):2/4(pink):1/4(white). |
Test cross involves:
| 1. | crossing between two genotypes with recessive trait |
| 2. | crossing between two F1 hybrids |
| 3. | crossing the F1 hybrid with a double recessive genotype |
| 4. | crossing between two genotypes with the trait |
In Mendel's experiments with garden peas, round seed shape (RR) was dominant over wrinkled seeds (rr), and yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the F2 generation of the cross RRYY x rryy?
| 1. | Only round seeds with green cotyledons |
| 2. | Only wrinkled seeds with yellow cotyledons |
| 3. | Only wrinkled seeds with green cotyledons |
| 4. | Round seeds with yellow cotyledons and wrinkled seeds with yellow cotyledons |
Which one of the following is an example of polygenic inheritance?
1. Flower colour in Mirabilis jalapa
2. Production of male honey bee
3. Pod shape in garden pea
4. Skin colour in humans
In pea plants, yellow seeds are dominant to green. If a heterozygous yellow-seeded plant is crossed with a green-seeded plant, what ratio of yellow and green-seeded plants would you expect in F1generation?
1. 50:50
2. 9:1
3. 1:3
4. 3:1
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