If two persons 'AB' blood group marry and have sufficiently large number of children, these children could be classified as 'A' blood group : 'AB' blood group : 'B' blood group in 1 : 2 : 1 ratio. Modern technique of protein electrophoresis reveals presence of both 'A' and 'B' type proteins in 'AB' blood group individuals. This is an example of

(1) codominance

(2) incomplete dominance

(3) partial dominance

(4) complete dominance 

Subtopic:  Dominance Deviation from Mendel: 2 |
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The incorrect statement with regard to haemophilia is

(1) it is a sex-linked disease

(2) it is a recessive disease

(3) it is a dominant disease

(4) a single protein involved in the clotting of blood effected

Subtopic:  Mendelian Disorders: Hemophilia |
 82%
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F2 generation in a Mendelian cross showed that both genotypic and phenotypic ratios are same as 1:2:1. It represents a case of 

(1) codominance

(2) dihybrid cross

(3) monohybrid cross with complete dominance

(4) monohybird cross the incomplete dominance

Subtopic:  Dominance Deviation from Mendel: 1 |
 68%
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Which one of the following cannot be explained on the basis of Mendel's Law of Dominance?

(1) The discrete unit controlling a particular character is called a factor

(2) Out of one pair of factors one is dominant, and the other is recessive

(3) Alleles do not show any blendings and both the characters recover as such in F2 generation.

(4) Factors occur in pairs

Subtopic:  Law of Segregation |
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ABO blood groups in humans are controlled by the gene I. It has three alleles — IA, IB and i. Since there are three different alleles, six different genotypes are possible. How many phenotypes can occur?

(1) Three

(2) One

(3) Four

(4) Two

Subtopic:  Dominance Deviation from Mendel: 2 |
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Select the correct statement from the ones given below with respect to dihybrid cross.

(1) Tightly linked genes on the same chromosome show higher recombinations

(2) Genes far apart on the same chromosome show very few recombinations

(3) Genes loosely linked on the same chromosome show similar recombinations as the tightly linked ones

(4) Tightly linked genes on the same chromosome show very few recombinations.

Subtopic:  Linkage |
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A common test to find the genotype or hybrid is by :

(1) crossing of one F2 progeny with male parent

(2) crossing of one F2 progeny with female parent

(3) studying the sexual behaviour of F1 progenies

(4) crossing of one F1 progeny with recessive parent

Subtopic:  Monohybrid Cross: Further Understanding |
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In pea plants, yellow seeds are dominant to green. If heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green plants would you expect in F1 generation ?

(1) 50 : 50

(2) 9 : 1

(3) 1 : 3

(4) 3 : 1

Subtopic:  Monohybrid Cross: 1 |
 72%
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In Mendel's experiments with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr), Yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the F2 generation of the cross RRYY x rryy ?

1. Only round seeds with green cotyledons

2. Only wrinkled with yellow cotyledons

3. Only wrinkled seeds with green cotyledons

4. Round seeds with yellow cotyledons and wrinkled seeds with yellow cotyledons.

Subtopic:  Dihybrid Cross Analysis |
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Study the pedigree chart of a family showing the inheritance of myotonic dystrophy.

 

The trait under study is 

1. dominant X-linked

2. recessive X-linked

3. autosomal dominant

4. recessive Y-linked.

Subtopic:  Pedigree Analysis: Problem Solving |
 74%
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